Tweepy過濾器無法正常工作

如果您只想查看所選推特ID的推文，Tweepy中有一項功能。Tweepy過濾器無法正常工作

streaming_api.filter(follow=("501088042","107536557",), track=Q)

不幸的是，它要麼沒有運作（高度懷疑），要麼我做錯了什麼。如果我設置follow=None該腳本功能完美。當我設置用戶ID時，它繼續工作，就好像我什麼也沒有改變。如何過濾我的信息流以僅使用我在follow中設置的ID？

這是代碼：

import sys 
import tweepy 
import webbrowser 
import MySQLdb 

Q = sys.argv[1:] 

db = MySQLdb.connect("localhost","user","password","db") 

auth = tweepy.OAuthHandler(CONSUMER_KEY, CONSUMER_SECRET) 
auth.set_access_token(ACCESS_TOKEN, ACCESS_TOKEN_SECRET) 

cur = db.cursor() 

class CustomStreamListener(tweepy.StreamListener): 

    def on_status(self, status): 

     try: 
      print "%s\t%s\t%s\t%s" % (status.text, 
             status.author.screen_name, 
             status.created_at, 
             status.source,) 

      cur.execute("INSERT INTO tweets VALUES (%s, %s, %s, %s)", (status.text, 
                     status.author.screen_name, 
                     status.created_at, 
                     status.source)) 

     except Exception, e: 
      print >> sys.stderr, 'Encountered Exception:', e 
      pass 

    def on_error(self, status_code): 
     print >> sys.stderr, 'Encountered error with status code:', status_code 
     return True # Don't kill the stream 

    def on_timeout(self): 
     print >> sys.stderr, 'Timeout...' 
     return True # Don't kill the stream 

streaming_api = tweepy.streaming.Stream(auth, CustomStreamListener(), timeout=60) 

print >> sys.stderr, 'Filtering the public timeline for "%s"' % (' '.join(sys.argv[1:]),) 

streaming_api.filter(follow=("501088042","107536557",), track=Q)

來源

2012-02-29 David Neudorfer

定了！

streaming_api.filter(follow=['501088042'], track=Q)

來源

2012-03-05 23:30:06

Tweepy過濾器無法正常工作

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