當彈出窗口關閉時，輸入自動擦除。我希望編輯文本返回與彈出按鈕被按下時放置的輸入

Question

我的問題是，我有一個彈出窗口，不保存輸入 編輯彈出窗口關閉時的文本。預期結果：我想要的是當彈出窗口關閉時，如果因爲任何原因我需要重新打開彈出窗口，我希望看到我放置的值。我已經嘗試過修改活動生命週期和onSaveInsanceState方法，但我的問題似乎沒有解決。出於某些原因，我的彈出窗口有它自己的生命。它基本上每次都會創建一個新的popUp實例。

  public class MainActivity extends Activity { 
       private Point p; 
       private Button b; 
       private TextView tv; 
       private PopupWindow popup; 
       private LayoutInflater layoutInflater; 
       private View layout; 
       private LinearLayout viewGroup; 
       private EditText etext; 
      //on create method 
        @Override 
      protected void onCreate(Bundle savedInstanceState) { 
      super.onCreate(savedInstanceState); 
      setContentView(R.layout.activity_main); 
      mainViewItems(); 
      onPause(); 
     } 
       //allows me to pause session 
        @Override 
       protected void onPause(){ 
     super.onPause(); 
      mainViewItems(); 

       } 

        // This method is in charge of instantiating the   
       // buttons,textviews, and allowing an event handler to 
       // call  
       showPopup() method. 
       public void mainViewItems(){ 
      b= (Button) findViewById(R.id.button1); 
      tv = (TextView) findViewById(R.id.textView1); 
        b.setOnClickListener(new OnClickListener(){ 
     @Override 
     public void onClick(View arg0) { 
        showPopup(MainActivity.this,p);}}); 

       } 

     @Override 
     public void onWindowFocusChanged(boolean hasFocus) { 

     int[] location = new int[2]; 
     b.getLocationOnScreen(location); 
     //Initialize the Point with x, and y positions 
     p = new Point(); 
     p.x = location[0]; 
     p.y = location[1]; 

    } 






    // The method that displays the popup. 
    private void showPopup(final Activity context,Point p) { 
     int popupWidth = 230; 
     int popupHeight = 190; 

     // Inflate the popup_layout.xml 
    viewGroup = (LinearLayout) context.findViewById(R.id.pop); 
    layoutInflater = (LayoutInflater) 
        context.getSystemService(Context.LAYOUT_INFLATER_SERVICE); 

    layout = layoutInflater.inflate(R.layout.popup_layout, 
                   viewGroup); 

    // Creating the PopupWindow 
     popup = new PopupWindow(layout,350,350, true); //context 
     popup.setContentView(layout);//layout 
     popup.setWidth(popupWidth); 
     popup.setHeight(popupHeight); 
     popup.setFocusable(true); 
     popup.setTouchable(true); 
     popup.setOutsideTouchable(false); 
     popup.update(); 


     int OFFSET_X = -100; 
     int OFFSET_Y = 100; 


     // Displaying the popup at the specified location, + offsets. 
     popup.showAtLocation(layout, Gravity.NO_GRAVITY, p.x +  
           OFFSET_X, p.y + OFFSET_Y); 

     etext = (EditText) layout.findViewById(R.id.editText1); 
     Button b2 = (Button) layout.findViewById(R.id.calculate); 

     b2.setOnClickListener(new OnClickListener() { 

     @Override 
     public void onClick(View v)  
        {tv.setText(etext.getText().toString());}}); 
     Button close = (Button) layout.findViewById(R.id.close); 


      close.setOnClickListener(new OnClickListener() { 

      @Override 
      public void onClick(View v) { popup.dismiss(); }}); 

        } 


         } 

Answer 1

您每次展示它時都會創建一個新的PopupWindow。你還會期望什麼 - 它是一個新的EditText窗口。解決此問題的最簡單方法是將最後輸入的字符串存儲在活動的成員變量中，並在顯示彈出窗口時將編輯文本設置爲該變量。