'QOAuth ::接口和QOAuth ::接口::運算符=（常量QOAuth ::接口和）' 是私有

Question

我試圖使用QOAuth卻收到以下錯誤：

錯誤：「QOAuth ::接口& QOAuth ::接口::運算符=（const的QOAuth ::接口&）」是私人

我的源代碼如下：

service.h

// ... 
class Service : public QObject 
{ 
    Q_OBJECT 

// ... 

private: 
    QOAuth::Interface *qoauth; 
}; 
// ... 

service.cpp

#include "service.h" 

Service::Service(QObject *parent) : 
    QObject(parent) 
{ 
*qoauth = new QOAuth::Interface; 
} 

QString Service::getAuthorizeUrl(QString consumerKey, QString consumerSecret){ 

    // set the consumer key and secret 
    qoauth->setConsumerKey(consumerKey); 
    qoauth->setConsumerSecret(bytes); 

    // ... 
} 

void Service::accessToken(QString url) { 
    // send a request to exchange Request Token for an Access Token 
    QOAuth::ParamMap reply = qoauth->accessToken(url, QOAuth::POST, m_token, m_tokenSecret, QOAuth::HMAC_SHA1); 

    // ... 
} 

我不明白指針不夠，也可能是原因...提前

感謝。

Answer 1

*qoauth = new QOAuth::Interface;是不正確的，因爲new回報指針的對象應該是qoauth = new QOAuth::Interface;