更新: 我使用「\ N」在遊戲存檔方法,它是在API中規定的不同的每一行。這意味着readLine應正確找到文件中的每一行,分配它的值並在讀取最後一行後關閉。讀數(分配)在Java中txt.file值
包含字符串:不過,我仍然得到 「空」(空指針異常)作爲輸出...
這是怎麼空的API中規定:
(的readLine)返回行的內容,不包括任何 行終止符,或NULL,如果流的末尾,一直達到
我想讀取一個txt文件並將其行分配到一個int [] []數組。
這是文件如何我savegame.txt看起來像一個例子:
0
0
-1
0
1
-1
1
0
0
每一行代表一個INT-值。我的saveGame方法將數組「gameBoard」的當前int值寫入上面顯示的文件中。這個例子代表了以下游戲狀態:
| | O
| X | O
X | |
但是,當我嘗試閱讀我的loadGame方法,其中分配每個savegame.txt文件個人gameBoard位置[0] [0]至[2] [2]其各自的價值觀,我得到null作爲輸出和遊戲以emp開始ty數組。從我的邏輯來看,我的loadGame方法應該單獨讀取每一行,並將其String-value解析爲一個Integer,它可以被我的int [] []數組gameBoard解釋。 我想知道爲什麼這不能正常工作。
FileManagement.class
package storagePack;
import structurePack.Board;
import java.io.*;
import java.util.Scanner;
/**
* The FileManagement-Class is responsible for the saving and loading of gamedata.
* It saves the current gameBoard and reads it with the loadGame Method.
*/
public class FileManagement {
static String filename = "Savegame.txt";
/**
* Schema:
* (0,0) | (0,1) | (0,2)
* (1,0) | (1,1) | (1,2)
* (2,0) | (2,1) | (2,2)
*/
/**
* @param gameBoard, the currently active Array from the Board.class.
* @throws Exception, FileNotFoundException
*/
public static void saveGame(int[][] gameBoard) throws Exception {
//serialization
PrintWriter writer;
try {
writer = new PrintWriter(new FileOutputStream(filename), false);
for (int i = 0; i < gameBoard.length; i++) {
for (int j = 0; j < gameBoard.length; j++) {
int entry = gameBoard[i][j];
writer.print(entry);
writer.println('\n');
}
}
writer.close();
} catch (Exception e) {
System.out.println(e.getMessage());
}
}
/**
* @throws Exception, FileNotFoundException
*/
public static void loadGame() throws Exception {
//deserialization
FileReader fileReader = new FileReader(filename);
BufferedReader bufferedReader = new BufferedReader (fileReader);
try {
structurePack.Board.gameBoard[0][0] = Integer.parseInt(bufferedReader.readLine());
structurePack.Board.gameBoard[0][1] = Integer.parseInt(bufferedReader.readLine());
structurePack.Board.gameBoard[0][2] = Integer.parseInt(bufferedReader.readLine());
structurePack.Board.gameBoard[1][0] = Integer.parseInt(bufferedReader.readLine());
structurePack.Board.gameBoard[1][1] = Integer.parseInt(bufferedReader.readLine());
structurePack.Board.gameBoard[1][2] = Integer.parseInt(bufferedReader.readLine());
structurePack.Board.gameBoard[2][0] = Integer.parseInt(bufferedReader.readLine());
structurePack.Board.gameBoard[2][1] = Integer.parseInt(bufferedReader.readLine());
structurePack.Board.gameBoard[2][2] = Integer.parseInt(bufferedReader.readLine());
fileReader.close();
bufferedReader.close();
} catch (Exception e) {
System.out.println(e.getMessage());
}
}
}
的readLine API-文檔
public String readLine()
throws IOException
Reads a line of text. A line is considered to be terminated by any one of a line feed ('\n'), a carriage return ('\r'), or a carriage return followed immediately by a linefeed.
Returns:
A String containing the contents of the line, not including any line-termination characters, or null if the end of the stream has been reached
Throws:
IOException - If an I/O error occurs
See Also:
Files.readAllLines(java.nio.file.Path, java.nio.charset.Charset)
如果您正在從文件中讀取數據,您爲什麼使用'Scanner(System.in)'? – SomeJavaGuy
嘗試'e.printStackTrace();'而不是'System.out.println(e.getMessage());'。這對於控制檯中的異常顯示是很好的做法,很可能會對你有所幫助。 – Paul
哦,我以爲我可以使用掃描儀......做我必須使用的BufferedReader的https://docs.oracle.com/javase/7/docs/api/java/io/BufferedReader.html – Dave