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請幫我做在php中的過程,以便我從變量中獲得數據。在這種情況下,我創建了一個用於創建xml文件的php文件。在這裏,我得到了數據,即頻道,我希望該頻道中的每位家長都能輸入數據。請參閱我的代碼:雙查詢從數據庫中檢索數據
<?php
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "";
$dbname = "db_epg";
mysql_connect($dbhost,$dbuser,$dbpass);
mysql_select_db($dbname);
$sql = "select distinct(channel_name) FROM epg";
$q = mysql_query($sql) or die(mysql_error());
$xml = "<timetable start='00:00' end='24:00' title='Friday, September 28th, 2011'>";
while($r = mysql_fetch_array($q)){
$CN = $r['channel_name'];
$xml .= "<channel>".$CN."</channel>";
}
$xml .= "</timetable>";
$sxe = new SimpleXMLElement($xml);
$sxe->asXML("epg.xml");
?>
而且從我的代碼的結果是:http://s9.postimage.org/rjsodf9mn/result.png
如果我想要做的每個數據信道的循環將是對孩子沒有任何數據,那麼我該怎麼辦?
我試圖在這個而部分做另一個查詢:
while($r = mysql_fetch_array($q)){
$CN = $r['channel_name'];
$xml .= "<channel>".$CN."</channel>";
$sql2 = "select * FROM epg where channel_name='".$CN."'";
$q2 = mysql_query($sql2) or die(mysql_error());
while($r2 = mysql_fetch_array($q2)){
$Mulai = date('H:i', strtotime($r2['waktu_mulai']));
$Selesai = date('H:i', strtotime($r2['waktu_akhir']));
$Title = $r2['judul'];
$Desk = $r2['sinopsis'];
$xml .= "<event start='".$Mulai."' end='".$Selesai."'>";
$xml .= "<title>".$Title."</title>";
$xml .= "<description>".$Desk."</description>";
$xml .= "</event>";
}
}
但我失敗了。有人能幫我嗎??
代碼是否給你一個錯誤?你是什麼意思「失敗」?預期的結果是什麼,你得到了什麼? – Fanis