PHP - 表ID相同

Question

如何將相同的列（在本例中按「級別」排序）放在一起？我在我的數據庫中按等級列出他們的高分。如果他們是同一級別，我希望他們擁有相同的ID。

但我不想在別人上顯示ID。只有第一個。 下面是一個例子：

ID - Name - Level 
1 - John - 5 
2 - David - 4 
3 - Josh - 3 
    - Sam - 3 
4 - George - 2 

所以我希望把它們放在一起，但如果他們有相同的水平，只有第一個顯示的ID。

我不希望它看起來像：

1 - John - 5 
2 - David - 4 
3 - Josh - 3 
3 - Sam - 3 
4 - George - 2 

現在，它是剛剛上市的每一個人，並給予每一個唯一的ID。即使他們有相同的「水平」。 我該如何解決這個問題？這裏是我的代碼：

<?php 
      $sql = mysql_query("SELECT * FROM rookstayers ORDER BY level DESC LIMIT 0, 500"); 
      $id = 1; 
      while($row = mysql_fetch_array($sql)){ 
       $name = $row['name']; 
       $level = $row['level']; 
       $world = $row['world']; 
       $account = $row['accountstatus']; 
       $status = $row['onlinestatus']; 
       $onrow = ''; 
       $typeServ = ''; 

       $player_name = urlencode($name); 

       if ($status == 1){ 
        $status = 'Online'; 
        $onrow = 'online'; 
       } else { 
        $status = 'Offline'; 
        $onrow = 'offline'; 
       } 

       if ($account == 'Premium Account'){ 
        $account = 'Premium'; 
       } else { 
        $account = 'Free'; 
       } 

       if ($world == 'Aurora' || $world == 'Aurera'){ 
        $typeServ = 'active'; 
       } else { 
        $typeServ = ''; 
       } 

      echo "<tr class=" . $typeServ . ">"; 
      echo "<td>" . $id . "</td>"; 
       echo "<td>" . $name . " <a href='http://www.tibia.com/community/?subtopic=characters&name=" . $player_name . "' target='_blank'><img src='../../img/websites/tibia.png' title='Tibia Profile'></a><a href='http://www.pskonejott.com/otc_display.php?character=" . $player_name . "' target='_blank'><img src='../../img/websites/pskonejott.png' title='Pskonejott'></a>" . "</td>"; 
       echo "<td>" . $level . "</td>"; 
       echo "<td>" . $world . "</td>"; 
       echo "<td>" . $account . "</td>"; 
       echo "<td class=" . $onrow . ">" . $status . "</td>"; 
      echo "</tr>"; 

      $id++; 
} 
      echo "</tbody>"; 
     echo "</table>"; 
?> 

Answer 1

你可以爲當前級別創建一個臨時變量，並檢查它是否在輸出中顯示id。

$id = 1; 
    $last_player_lvl = ''; 
    while($row = mysql_fetch_array($sql)){ 
     ///.... 

    echo "<tr class=" . $typeServ . ">"; 
         echo "<td>" . (($last_player_lvl == $row['level']) ? '' : $id) . "</td>"; 
          echo "<td>" . $name . " <a href='http://www.tibia.com/community/?subtopic=characters&name=" . $player_name . "' target='_blank'><img src='../../img/websites/tibia.png' title='Tibia Profile'></a><a href='http://www.pskonejott.com/otc_display.php?character=" . $player_name . "' target='_blank'><img src='../../img/websites/pskonejott.png' title='Pskonejott'></a>" . "</td>"; 
          echo "<td>" . $level . "</td>"; 
          echo "<td>" . $world . "</td>"; 
          echo "<td>" . $account . "</td>"; 
          echo "<td class=" . $onrow . ">" . $status . "</td>"; 
         echo "</tr>"; 
if($last_player_lvl == $row['level']){ 
    $id = $id; 
}else{ 
    $id++; 
} 
$last_player_lvl = $row['level']; 
//....