添加到

Question

我回來通過PDO的關聯數組具有以下結構的多維關聯數組（在PHP）：

Array 
(
    [0] => Array 
     (
      [pesttopicID] => 42 
      [sPestName] => CMSM Trap Surveying and Pest Management 
      [quizID] => 609 
      [bTier1] => 1 
      [sDesc] => Workshop assessment 
     ) 

    [1] => Array 
     (
      [pesttopicID] => 34 
      [sPestName] => Trap Surveyor 
      [quizID] => 451 
      [bTier1] => 1 
      [sDesc] => Competency for CM OAP 
     ) 
) 

欲一個鍵 - 值對添加到「內部」陣列，但我試圖用發佈的解決方案來增加關聯數組的一般問題的所有嘗試...

: 
$results = $statement->fetchAll(PDO::FETCH_ASSOC); 
$newkey='myNewKey'; 
$newval='myNewValue'; 
foreach($results as $row){ 
    $results[][$newkey] = $newval; 
    foreach ($row as $key=>$value){ 
    ... some reporting stuff 
    } 
} 

...導致對被添加到「外」排列如

Array 
(
    [0] => Array <---- I want the new pair in this "inner" array 
     ( 
      [pesttopicID] => 42 
      [sPestName] => CMSM Trap Surveying and Pest Management 
      [quizID] => 609 
      [bTier1] => 1 
      [sDesc] => Workshop assessment 
     ) 

    [1] => Array <---- I want the new pair in this "inner" array 
     ( 
      [pesttopicID] => 34 
      [sPestName] => Trap Surveyor 
      [quizID] => 451 
      [bTier1] => 1 
      [sDesc] => Competency for CM OAP 
     ) 

    [2] => Array 
     (
      [myNewKey] => myNewValue 
     ) 
) 

這可能嗎？

感謝/湯姆

Answer 1

你必須給它象下面這樣： -

$newkey='myNewKey'; 
$newval='myNewValue'; 
foreach($results as &$row){ //use reference variable 
    $row[$newkey] = $newval;// remove the second foreach if not necessary 
    //if second foreach is necessary then add it no problem 
} 

輸出： - https://eval.in/856983

或者你也可以做到這樣也： -

$newkey='myNewKey'; 
$newval='myNewValue'; 
foreach($results as $key=>$row){ //use key now 
    $results[$key][$newkey] = $newval;// remove the second foreach if not necessary 
    //if second foreach is necessary then add it no problem 
} 

輸出： - https://eval.in/856987

Answer 2

嘗試

foreach($results as &$result) 
{ 
    $result[$key] = $value; 
} 

編輯：SRY我犯了一個錯誤