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所以基本上,我有一個函數getPayments()。這個函數應該執行一個查詢,從多個表中選擇(加入)。這是我的代碼返回語句不返回任何東西
function getPayments($userid, $schoolyear) {
$stmt = $this->con->prepare("SELECT tbl_payment.payment_receipt_type AS RType, tbl_payment.payment_receipt_number AS RNumber, tbl_feetype.feetype_name AS FName, tbl_payment.payment_amount AS PAmount, tbl_month.month_date AS MDate, tbl_payment.payment_dateadded AS PAdded
FROM tbl_payment
INNER JOIN tbl_student ON tbl_student.student_id = tbl_payment.student_id
INNER JOIN tbl_schoolyear ON tbl_schoolyear.schoolyear_id = tbl_payment.schoolyear_id
INNER JOIN tbl_feetype ON tbl_feetype.feetype_id = tbl_payment.feetype_id
INNER JOIN tbl_month ON tbl_month.month_id = tbl_payment.month_id
WHERE tbl_payment.schoolyear_id = ? AND tbl_payment.student_id = ? ORDER BY payment_dateadded DESC");
$stmt->bind_param("ss", $userid, $schoolyear);
$stmt->execute();
$stmt->bind_result($RType, $RNumber, $FName, $PAmount, $MDate, $PAdded);
$payments = array();
while ($stmt->fetch()) {
$temp = array();
$temp['paymenttype'] = $RType;
$temp['receiptnumber'] = $RNumber;
$temp['feename'] = $FName;
$temp['paymentamount'] = $PAmount;
$temp['monthname'] = $MDate;
$temp['paymentdate'] = $PAdded;
array_push($payments, $temp);
}
return $payments;
}
以我index.php文件:
//getting payment details for a user
$app->get('/payment/{id}/{sy}', function (Request $request, Response $response) {
$route = $request->getAttribute('route');
// $userid = $request->getAttribute('id');
$userid = $route->getArgument('id');
$schoolyear = $route->getArgument('sy');
// $schoolyear = $request->getAttribute('sy');
$db = new DbOperation();
$payments = $db->getPayments($userid, $schoolyear);
$response->getBody()->write(json_encode(array("payments" => $payments)));
});
^這行代碼會從getPayment()函數返回的數組結果然後將其編碼爲JSON。
的問題是,在郵差測試我的API後,郵差只給了我這樣的結果
{"payments":[]}
請幫助我。謝謝。 (對不起,我的英語不好)
你能確保你的MySQL查詢返回結果嗎? – Ice76
@ Ice76是的,在phpmyadmin中試過這個查詢,它返回結果。 – WeShallCode