更新兩個表Codeigniter

Question

我試圖同時更新2個表tbl_loanledger和tbl_journal。兩個表具有相同的列，如modified_by, date_modified and deleted。

當我試圖運行此我輸入代碼在這裏，我得到一個錯誤：

錯誤號：在字段列表1052

列 'modified_by' 不明確

UPDATE` loan_ledger` as a，journal as b SET`modified_by` ='1'， `date_modified` ='2016-06-08'，`deleted` = 1 WHERE`a`.`id` ='823' AND` '```''823'

文件名：C：\ XAMPP \ htdocs中\系統\系統\數據庫\ DB_driver.php

行號：331

這是一個關於如何更新笨2代表的正確方法？

型號

public function delete($id){ 

    $data = array(
     'modified_by' => $this->ion_auth->user()->row()->id, 
     'date_modified' => date("Y-m-d"), 
     'deleted' => 1 
    ); 

    $this->db->set($data); 
    $this->db->where('a.id', $id); 
    $this->db->where('b.id', $id); 
    $this->db->update('loan_ledger as a, journal as b'); 

} 

但如果我只是更新一個表，它是工作，這裏是代碼：

public function delete($id){ 

    $data = array(
     'modified_by' => $this->ion_auth->user()->row()->id, 
     'date_modified' => date("Y-m-d"), 
     'deleted' => 1 
    ); 
    $this->db->where('id', $id); 
    $this->db->update(tbl_loanledger, $data); 

} 

Answer 1

沒有使用加入只是寫兩個單獨的更新查詢爲

// first 
    $this->db->set('a.modified_by', $this->ion_auth->user()->row()->id); 
    $this->db->set('a.date_modified', date("Y-m-d")); 
    $this->db->set('a.deleted', 1); 
    $this->db->where('a.id', $id); 
    $this->db->update('loan_ledger as a'); 
    // second 
    $this->db->set('b.modified_by', $this->ion_auth->user()->row()->id); 
    $this->db->set('b.date_modified', date("Y-m-d")); 
    $this->db->set('b.deleted', 1); 
    $this->db->where('b.id', $id); 
    $this->db->update('journal as b'); 

Answer 2

試試這個

public function delete($id){ 

$data = array(
    'a.modified_by' => $this->ion_auth->user()->row()->id, 
    'a.date_modified' => date("Y-m-d"), 
    'b.modified_by' => $this->ion_auth->user()->row()->id, 
    'b.date_modified' => date("Y-m-d"), 
    'deleted' => 1 
); 

$this->db->set($data); 
$this->db->where('a.id', $id); 
$this->db->where('b.id', $id); 
$this->db->update('loan_ledger as a, journal as b'); 

} 

Answer 3

<?php 
$this->db->set('a.modified_by', $this->ion_auth->user()->row()->id); 
$this->db->set('a.date_modified', date("Y-m-d")); 
$this->db->set('a.deleted', 1); 

$this->db->set('b.modified_by', $this->ion_auth->user()->row()->id); 
$this->db->set('b.date_modified', date("Y-m-d")); 
$this->db->set('b.deleted', 1); 

$this->db->where('a.id', $id); 
$this->db->where('a.id = b.id'); 
$this->db->update('loan_ledger as a, journal as b'); 
?>