連續追加號碼爲文件名

Question

我有一個像

Ortho234.phy 
Ortho671.phy 
Ortho880.phy and so on 

文件列表，我想爲陣列作業重命名爲

Ortho234.1.phy 
Ortho671.2.phy 
Ortho880.3.phy 

我試過，但這種替換，只是名稱該文件爲1.phy，2.phy等。

a=1 
for i in *.phy; do 
    new=$(printf "%04d.phy" "$a") 
    mv -- "$i" "$new" 
    let a=a+1 
done 

Answer 1

以下命令的任何人會做你的工作

c=0 rename 's/\./sprintf(".%d.",++$ENV{c})/e' *.phy 

rename 's/\./".".++$a."."/e' *.phy     

rename '$a++; s/\./.$a./e' *.phy     

n=1;for f in *.phy; do mv "$f" "${f%.*}.$n.${f##*.}"; n=$((n+1)); done 

要麼

它執行perl s///表達，並從 原來以進行重命名替換字符串。在替換字符串我用 sprintf格式化的名字，在這裏我使用環境變量c作爲 計數器

$ touch Ortho234.phy Ortho671.phy Ortho880.phy 

$ ls *.phy -1 
Ortho234.phy 
Ortho671.phy 
Ortho880.phy 

$ c=0 rename 's/\./sprintf(".%d.",++$ENV{c})/e' *.phy 

$ ls *.phy -1 
Ortho234.1.phy 
Ortho671.2.phy 
Ortho880.3.phy 

OR

$ touch Ortho234.phy Ortho671.phy Ortho880.phy 

$ ls *.phy -1 
Ortho234.phy 
Ortho671.phy 
Ortho880.phy 

$ n=1;for f in *.phy; do mv "$f" "${f%.*}.$n.${f##*.}"; n=$((n+1)); done 

$ ls *.phy -1 
Ortho234.1.phy 
Ortho671.2.phy 
Ortho880.3.phy 

OR

$ touch Ortho234.phy Ortho671.phy Ortho880.phy 

$ ls *.phy -1 
Ortho234.phy 
Ortho671.phy 
Ortho880.phy 

$ rename 's/\./".".++$a."."/e' *.phy 

$ ls *.phy -1 
Ortho234.1.phy 
Ortho671.2.phy 
Ortho880.3.phy 

OR

$ touch Ortho234.phy Ortho671.phy Ortho880.phy 

$ ls *.phy -1 
Ortho234.phy 
Ortho671.phy 
Ortho880.phy 

$ rename '$a++; s/\./.$a./e' *.phy 

$ ls *.phy -1 
Ortho234.1.phy 
Ortho671.2.phy 
Ortho880.3.phy 

Answer 2

這應該做的工作：

filepart是文件名，不帶擴展名。

Answer 3

awk -F\. '{print $1"."NR"."$2}' file 

Ortho234.1.phy 
Ortho671.2.phy 
Ortho880.3.phy 

Answer 4

awk指令還有助於獲得所需的輸出。 NR給出的行號和上.分割輸入和陣列重寫按所需要的像以下

awk '{split($0,a,"."); print a[1]"."NR"."a[2]}' file 

文件是包含下列值

Ortho234.phy 
Ortho671.phy 
Ortho880.phy