通過使用一個提交按鈕將數據從2個表單傳遞到數據庫

我對PHP和HTML相當陌生，自從我一直試圖解決這個問題以來，已經有2天了。通過使用一個提交按鈕將數據從2個表單傳遞到數據庫

我想從這些表單傳入數據到我的數據庫的表中，但我無法做到這一點，因爲這兩個表單只使用相同的標籤。 The 2 Forms
The table to which I'm trying to send the data

<?php 
    if(isset($_POST['submitted'])) 
    { 
     include('config/config1.php'); 
     global $conn; /* para makuha ang variable galing sa config/config1. */ 

     $firstname1 = $_POST["firstname"]; 
     $middlename1 = $_POST["middlename"]; 
     $lastname1 = $_POST['lastname']; 
     $sex1 = $_POST['sex']; 
     $household_head1 = $_POST['household_head']; 
     $household1 = $_POST['household']; 
     $civil_status1 = $_POST['civil_status']; 
     $bday1 = $_POST['birthdate']; 
     $bplace1 = $_POST['birthplace']; 
     $citizenship1 = $_POST['citizenship']; 
     $occupation1 = $_POST['occupation']; 
     $sponsors_female1 = $_POST['sponsors_female']; 
     $sponsors_male1 = $_POST['sponsors_male']; 
     $email1 = $_POST['email']; 
     $date_of_seminar1 = $_POST['date_of_seminar']; 
     /****  Query  ****/ 
     $insrtBptm = "INSERT INTO parishioner (firstname,middlename,lastname,sex,household_head,household,civil_status,birthdate,birthplace,citizenship,occupation,sponsors_female,sponsors_male,email,date_of_seminar) 
         VALUES ('$firstname1','$middlename1','$lastname1','$sex1','$household_head1','$household1','$civil_status1','$bday1','$bplace1','$citizenship1','$occupation1','$sponsors_female1','$sponsors_male1','$email1','$date_of_seminar1')"; 
     $update = "UPDATE parishioner SET Parishioner_idParishioner = idParishioner 
        WHERE Parishioner_idParishioner IS NULL AND idParishioner IS NOT NULL"; 
     header("Location:Home.php"); 
     /****  Validation ****/ 
     if(!mysqli_query($conn,$insrtBptm)) 
     { 
      die("Error not queried". mysqli_error()); 
     } 
     if(!mysqli_query($conn,$update)) 
     { 
      die("Update error !". mysqli_connect_error()); 
     } 
     mysqli_close($conn); 
    } 
?>

來源

2015-12-23 Jake152

您可以使用所有字段的單個表單@ Jake152 – Gayathri

從您的屏幕快照中，提交按鈕僅發佈丈夫表單的數據。 – Gayathri

而不是使用兩個表單的，你應該使用單一形式併爲丈夫和妻子相同的字段，你可以使用數組名=「妻子[FIRST_NAME]」和丈夫的名字=「丈夫[FIRST_NAME]」提交你會得到兩個陣列的妻子和丈夫 – softsdev

我怎麼會做它，創建兩個Wife和Husband，然後他們的前綴名稱input與wi_和hu_分別一個單一的形式，一旦形式提交然後我會在服務器端進行處理，驗證/驗證後，我會查詢插入兩行數據與各自的輸入。

來源

2015-12-23 07:21:59

不用擔心！爲php創建另一個第二個變量（即：firstname2，middlename2等）。然後做這個魔法

$insrtMar = "INSERT INTO parishioner (firstname,middlename,lastname,sex,household_head,household,civil_status,birthdate,birthplace,citizenship,occupation,sponsors_female,sponsors_male,email,date_of_seminar) VALUES ('$firstname1','$middlename1','$lastname1','$sex1','$household_head1','$household1','$civil_status1','$bday1','$bplace1','$citizenship1','$occupation1','$sponsors_female1','$sponsors_male1','$email1','$date_of_seminar1'),('$firstname2','$middlename2','$lastname2','$sex2','$household_head2','$household2','$civil_status2','$bday2','$bplace2','$citizenship2','$occupation2','$sponsors_female2','$sponsors_male2','$email2','$date_of_seminar2')";

所以對於短查詢：INSERT INTO 表名（COLUMNNAMES）VALUES（* 1 PHP變量），（*第二PHP變量）

中提琴！

來源

2015-12-23 15:03:56 Shulz

通過使用一個提交按鈕將數據從2個表單傳遞到數據庫

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