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動態獲取父元素並處理xml的動態子元素xslt

2017-03-03 71 views
2

我嘗試遍歷父節點的獨特子元素。框架預期的xml 下面是我的xml。動態獲取父元素並處理xml的動態子元素xslt

<NewDataSet> 
<caseParticipants> 
<Litigants>PORTFOLIO RECOVERY ASSOCIATES</Litigants> 
<Attorneys>MANISCALCO, ANTHONY JOSEPH</Attorneys> 
</caseParticipants> 
<caseParticipants> 
<Litigants>PLAINTIFF</Litigants> 
<Attorneys>Plaintiff Attorney</Attorneys> 
</caseParticipants> 
<caseParticipants> 
<Litigants /> 
<Attorneys /> 
<caseProceedings> 
<Date>05/12/2015</Date> 
<Details>PETITION/COMPLAINT NO DOC#</Details> 
</caseProceedings> 
<caseProceedings> 
<Date>05/12/2015</Date> 
<Details>ASM: SMALL CLAIMS $501-$2,500</Details> 
</caseProceedings> 
<caseCalendar> 
<Date>06/30/2015 13:00:00</Date> 
<Docket_x0020_Type>PRETRIAL CONF</Docket_x0020_Type> 
<Judge>LANDT, ROBERT E</Judge> 
<Location>XX : COURTR</Location> 
</caseCalendar> 
<caseFinancialSummary> 
<Column1>Assessment Total:</Column1> 
<Column2>$185.00</Column2> 
</caseFinancialSummary> 
<caseFinancialSummary> 
<Column1>Assessment Paid:</Column1> 
<Column2>$185.00</Column2> 
</caseFinancialSummary> 
<caseFinancialSummary> 
<Column1>Assessment Due:</Column1> 
<Column2>$0.00</Column2> 
</caseFinancialSummary> 
<caseFinancialSummary> 
<Column1>Restitution Total:</Column1> 
<Column2>$0.00</Column2> 
</caseFinancialSummary> 
<caseFinancialSummary> 
<Column1>Restitution Paid:</Column1> 
<Column2>$0.00</Column2> 
</caseFinancialSummary> 
<caseFinancialSummary> 
<Column1>Restitution Due:</Column1> 
<Column2>$0.00</Column2> 
</caseFinancialSummary> 
<caseFinancialSummary /> 
<caseFinancialdetails> 
<Assessment_x0020_Due>$185.00</Assessment_x0020_Due> 
<Assessment_x0020_Paid>$185.00</Assessment_x0020_Paid> 
<Restitution_x0020_Due>$0.00</Restitution_x0020_Due> 
<Restitution_x0020_Paid>$0.00</Restitution_x0020_Paid> 
</caseFinancialdetails> 
</NewDataSet>

我需要轉置爲像下面的XML。

<searchResult> 
<caseDetails> 
    <caseParticipants Label="Participants"> 
    <row> 
     <colhead id="1" align="left" bold="no">Litigants</colhead> 
     <colhead id="2" align="left" bold="no">Attorneys</colhead> 
    </row> 
    <row> 
     <cell id="1">Portfolio Recovery Associates</cell> 
     <cell id="2">Maniscalco, Anthony Joseph</cell> 
    </row> 
    <row> 
     <cell id="1">Plaintiff</cell> 
     <cell id="2">Plaintiff Attorney</cell> 
    </row> 
    <row> 
     <cell id="1" /> 
     <cell id="2" /> 
    </row> 
    </caseParticipants> 
    <caseProceedings Label="Proceedings"> 
    <row> 
     <colhead id="1" align="left" bold="no">Date</colhead> 
     <colhead id="2" align="left" bold="no">Details</colhead> 
    </row> 
    <row> 
     <cell id="1">05/12/2015</cell> 
     <cell id="2">Petition/Complaint no Doc#</cell> 
     <document available="No" /> 
    </row> 
    <row> 
     <cell id="1">05/12/2015</cell> 
     <cell id="2">Asm: Small Claims $501-$2,500</cell> 
     <document available="No" /> 
    </row> 
    </caseProceedings> 
    <caseCalendar Label="Calendar"> 
    <row> 
     <colhead id="1" align="left" bold="no">Date</colhead> 
     <colhead id="2" align="left" bold="no">Docket Type</colhead> 
     <colhead id="3" align="left" bold="no">Judge</colhead> 
     <colhead id="4" align="left" bold="no">Location</colhead> 
     <colhead id="5" align="left" bold="no">Prosecutor</colhead> 
     <colhead id="6" align="left" bold="no">Defendant Attorney</colhead> 
    </row> 
    <row> 
     <cell id="1">06/30/2015 13:00:00</cell> 
     <cell id="2">Pretrial Conf</cell> 
     <cell id="3">Landt, Robert E</cell> 
     <cell id="4">Xx : Courtr</cell> 
     <cell id="5" /> 
     <cell id="6" /> 
    </row> 
    </caseCalendar> 
    <caseFinancialSummary Label="Financial Summary"> 
    <row> 
     <colhead id="1" align="right" bold="no" /> 
     <colhead id="2" align="left" bold="no" /> 
    </row> 
    <row> 
     <cell id="1">Assessment Total:</cell> 
     <cell id="2">$185.00</cell> 
    </row> 
    <row> 
     <cell id="1">Assessment Paid:</cell> 
     <cell id="2">$185.00</cell> 
    </row> 
    <row> 
     <cell id="1">Assessment Due:</cell> 
     <cell id="2">$0.00</cell> 
    </row> 
    <row> 
     <cell id="1">Restitution Total:</cell> 
     <cell id="2">$0.00</cell> 
    </row> 
    <row> 
     <cell id="1">Restitution Paid:</cell> 
     <cell id="2">$0.00</cell> 
    </row> 
    <row> 
     <cell id="1">Restitution Due:</cell> 
     <cell id="2">$0.00</cell> 
    </row> 
    </caseFinancialSummary> 
    <caseFinancialDetails Label="Financial Details"> 
    <row> 
     <colhead id="1" align="left" bold="no">Assessment Due</colhead> 
     <colhead id="2" align="left" bold="no">Assessment Paid</colhead> 
     <colhead id="3" align="left" bold="no">Restitution Due</colhead> 
     <colhead id="4" align="left" bold="no">Restitution Paid</colhead> 
     <colhead id="5" align="left" bold="no">Payment Date</colhead> 
    </row> 
    <row> 
     <cell id="1">$185.00</cell> 
     <cell id="2">$185.00</cell> 
     <cell id="3">$0.00</cell> 
     <cell id="4">$0.00</cell> 
     <cell id="5" /> 
    </row> 
    </caseFinancialDetails> 
</caseDetails>

我想只有一個像下面caseParticipant部分。我需要爲所有節點這樣做，而不必提供元素名稱。因爲我每次都得到不同類型的父母和孩子的元素。

XSLT代碼：

<xsl:template match="caseParticipants"> 
<xsl:variable name="vrtfEvalResult"> 
<xsl:call-template name="eval"> 
    <xsl:with-param name="pPath" select="'/NewDataSet/caseParticipants'"/> 
</xsl:call-template> 
</xsl:variable> 
<row> 
<cell id="1"><xsl:value-of select="Litigants" /></cell> 
<cell id="2"><xsl:value-of select="Attorney" /></cell> 
</row> 
</xsl:template> 
<xsl:template match="text()"/> 
<xsl:template match="Path" name="eval"> 
<xsl:param name="pPath" select="."/> 
<xsl:param name="pContext" select="/"/> 
<xsl:choose> 
<!-- If there is something to evaluate --> 
<xsl:when test="string-length($pPath) >0"> 
    <xsl:variable name="vPath" select= 
     "substring($pPath,2)"/> 
    <xsl:variable name="vNameTest"> 
    <xsl:choose> 
    <xsl:when test="not(contains($vPath, '/'))"> 
    <xsl:value-of select="$vPath"/> 
    </xsl:when> 
    <xsl:otherwise> 
    <xsl:value-of select= 
     "substring-before($vPath, '/')"/> 
    </xsl:otherwise> 
    </xsl:choose> 
    </xsl:variable> 
    <xsl:call-template name="eval"> 
    <xsl:with-param name="pPath" select= 
    "substring-after($pPath, $vNameTest)"/> 
    <xsl:with-param name="pContext" select= 
    "$pContext/*[name()=$vNameTest]"/> 
    </xsl:call-template> 
    </xsl:when> 
<!-- Otherwise we have evaluated completely the path --> 
<xsl:otherwise> 
<xsl:copy-of select="$pContext"/> 
</xsl:otherwise> 
</xsl:choose> 
</xsl:template>

在此先感謝

來源

2017-03-03 Prabha

回答

0

我不得不重新考慮這個有點搞不定，但我認爲這是你想要什麼：

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> 
    <xsl:output method="xml" omit-xml-declaration="yes" indent="yes" /> 
    <xsl:key name="distinct-second-level-elements" match="/*/*" use="local-name()" /> 
    <xsl:template match="/NewDataSet"> 
    <searchResults> 
     <caseDetails> 
     <xsl:for-each select="*[count(.|key('distinct-second-level-elements', local-name())[1]) = 1]"> 
      <xsl:variable name="currNodeName" select="local-name()" /> 
      <xsl:element name="{$currNodeName}"> 
      <xsl:attribute name="Label"> 
       <xsl:value-of select="substring-after($currNodeName, 'case')" /> 
      </xsl:attribute> 
      <row> 
       <xsl:for-each select="./*"> 
       <colhead id="{position()}" align="left" bold="no"> 
        <xsl:value-of select="local-name(.)" /> 
       </colhead> 
       </xsl:for-each> 
      </row> 
      <xsl:for-each select="//*[local-name() = $currNodeName]"> 
       <row> 
       <xsl:for-each select="./*"> 
        <cell id="{position()}"> 
        <xsl:value-of select="." /> 
        </cell> 
       </xsl:for-each> 
       </row> 
      </xsl:for-each> 
      </xsl:element> 
     </xsl:for-each> 
     </caseDetails> 
    </searchResults> 
    </xsl:template> 
    <xsl:template match="text()" /> 
</xsl:stylesheet>
  1. 使用一個鍵來獲得不同的二級節點名稱，並遍歷該關鍵字a la Muenchian Grouping - 這顯然是我寫的關於在XSLT標籤，這些天;）
  2. 鳥巢一些for-each ES在那裏搶其他節點的孩子具有相同的名稱和佈局的行/細胞

所有這些都是使用像做local-name()和深入的選擇器（例如， /*/*），所以只要你的結構保持一致，它應該工作，不管節點名稱。

一注 - id attributes should be unique in a document，所以這在技術上是無效的XML - 但我假設它只是下游用戶不遵循標準的要求非常正確。如果情況並非如此，如果可能的話，您應該爲該屬性選擇一個不同的名稱。

輸出：

<searchResults> 
    <caseDetails> 
    <caseParticipants Label="Participants"> 
     <row> 
     <colhead id="1" align="left" bold="no">Litigants</colhead> 
     <colhead id="2" align="left" bold="no">Attorneys</colhead> 
     </row> 
     <row> 
     <cell id="1">PORTFOLIO RECOVERY ASSOCIATES</cell> 
     <cell id="2">MANISCALCO, ANTHONY JOSEPH</cell> 
     </row> 
     <row> 
     <cell id="1">PLAINTIFF</cell> 
     <cell id="2">Plaintiff Attorney</cell> 
     </row> 
     <row> 
     <cell id="1"></cell> 
     <cell id="2"></cell> 
     </row> 
    </caseParticipants> 
    <caseProceedings Label="Proceedings"> 
     <row> 
     <colhead id="1" align="left" bold="no">Date</colhead> 
     <colhead id="2" align="left" bold="no">Details</colhead> 
     </row> 
     <row> 
     <cell id="1">05/12/2015</cell> 
     <cell id="2">PETITION/COMPLAINT NO DOC#</cell> 
     </row> 
     <row> 
     <cell id="1">05/12/2015</cell> 
     <cell id="2">ASM: SMALL CLAIMS $501-$2,500</cell> 
     </row> 
    </caseProceedings> 
    <caseCalendar Label="Calendar"> 
     <row> 
     <colhead id="1" align="left" bold="no">Date</colhead> 
     <colhead id="2" align="left" bold="no">Docket_x0020_Type</colhead> 
     <colhead id="3" align="left" bold="no">Judge</colhead> 
     <colhead id="4" align="left" bold="no">Location</colhead> 
     </row> 
     <row> 
     <cell id="1">06/30/2015 13:00:00</cell> 
     <cell id="2">PRETRIAL CONF</cell> 
     <cell id="3">LANDT, ROBERT E</cell> 
     <cell id="4">XX : COURTR</cell> 
     </row> 
    </caseCalendar> 
    <caseFinancialSummary Label="FinancialSummary"> 
     <row> 
     <colhead id="1" align="left" bold="no">Column1</colhead> 
     <colhead id="2" align="left" bold="no">Column2</colhead> 
     </row> 
     <row> 
     <cell id="1">Assessment Total:</cell> 
     <cell id="2">$185.00</cell> 
     </row> 
     <row> 
     <cell id="1">Assessment Paid:</cell> 
     <cell id="2">$185.00</cell> 
     </row> 
     <row> 
     <cell id="1">Assessment Due:</cell> 
     <cell id="2">$0.00</cell> 
     </row> 
     <row> 
     <cell id="1">Restitution Total:</cell> 
     <cell id="2">$0.00</cell> 
     </row> 
     <row> 
     <cell id="1">Restitution Paid:</cell> 
     <cell id="2">$0.00</cell> 
     </row> 
     <row> 
     <cell id="1">Restitution Due:</cell> 
     <cell id="2">$0.00</cell> 
     </row> 
     <row /> 
    </caseFinancialSummary> 
    <caseFinancialdetails Label="Financialdetails"> 
     <row> 
     <colhead id="1" align="left" bold="no">Assessment_x0020_Due</colhead> 
     <colhead id="2" align="left" bold="no">Assessment_x0020_Paid</colhead> 
     <colhead id="3" align="left" bold="no">Restitution_x0020_Due</colhead> 
     <colhead id="4" align="left" bold="no">Restitution_x0020_Paid</colhead> 
     </row> 
     <row> 
     <cell id="1">$185.00</cell> 
     <cell id="2">$185.00</cell> 
     <cell id="3">$0.00</cell> 
     <cell id="4">$0.00</cell> 
     </row> 
    </caseFinancialdetails> 
    </caseDetails> 
</searchResults>

來源

2017-03-03 13:43:08

+0

非常感謝，這是我所期望的...... – Prabha

+0

沒問題 - 我的經驗法則是，每當我想要一個「獨特」或XSLT「組」，再想想關於如何使用「鑰匙」去那裏 –

+0

好的確定......感謝您的指導.. – Prabha

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