您的代碼似乎有些假設。這裏有一些完成了你所描述的事情。它創建三個標籤並初始化他們的文本。然後它啓動三個線程。每個線程在一段時間後更新與主線程中創建的標籤相關的tkinter變量。現在如果主線程真的需要更新,排隊確實有效,但是必須修改程序來完成更新。
import threading
import time
from tkinter import *
import queue
import sys
def createGUI(master, widget_var):
for i in range(3):
Label(master, textvariable=widget_var[i]).grid(row=i, column=0)
widget_var[i].set("Thread " + str(i) + " started")
def sometask(thread_id, delay, queue):
print("Delaying", delay)
time.sleep(delay)
tdict = {'id': thread_id, 'message': 'success'}
# You can put simple strings/ints, whatever in the queue instead
queue.put(tdict)
return
def updateGUI(master, q, widget_var, td):
if not q.empty():
tdict = q.get()
widget_var[tdict['id']].set("Thread " + str(tdict['id']) + " completed with status: " + tdict['message'])
td.append(1)
if len(td) == 3:
print("All threads completed")
master.after(1000, timedExit)
else:
master.after(100, lambda w=master,que=q,v=widget_var, tcount=td: updateGUI(w,que,v,td))
def timedExit():
sys.exit()
root = Tk()
message_q = queue.Queue()
widget_var = []
threads_done = []
for i in range(3):
v = StringVar()
widget_var.append(v)
t = threading.Thread(target=sometask, args=(i, 3 + i * 3, message_q))
t.start()
createGUI(root, widget_var)
updateGUI(root,message_q, widget_var, threads_done)
root.mainloop()