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我正在開發中，我有一個用的index.jsp形式的Web應用程序上傳文件到servlet：如何在將文件上傳到servlet後管理html網站？
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
import="com.uteva.AppWebNieve.ProcesadoExcel"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml"
xmlns:f="http://java.sun.com/jsf/core"
xmlns:h="http://java.sun.com/jsf/html"
xmlns:ui="http://java.sun.com/jsf/facelets" lang="es" xml:lang="es">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-
8859-1">
<title>AppWebInformesNieve</title>
</meta>
</head>
<body>
<form action="upload" method="post" enctype="multipart/form-data">
<input type="file" name="file" />
<input value="Subir Excel" type="submit" />
</form>
</body>
</html>
然後我上傳文件正確與我的java類：
@Override
protected void doPost(HttpServletRequest
request,HttpServletResponse response) throws ServletException,
IOException{
//***************AQUI MANEJAMOS LA SUBIDA DEL FICHERO LINCES DE INCIDENCIAS***********************
// Get the file location where it would be stored.
//String filePath = getServletContext().getInitParameter("file-upload");
boolean isMultipart;
int maxFileSize = 10000 * 1024;
int maxMemSize = 1000 * 1024;
File file ;
// Check that we have a file upload request
isMultipart = ServletFileUpload.isMultipartContent(request);
response.setContentType("text/html");
java.io.PrintWriter out = response.getWriter();
if(!isMultipart){ //No se ha podido subir el fichero
/*out.println("<html>");
out.println("<head>");
out.println("<title>Servlet upload</title>");
out.println("</head>");
out.println("<body>");
out.println("<p>No file uploaded</p>");
out.println("</body>");
out.println("</html>");*/
return;
}
DiskFileItemFactory factory = new DiskFileItemFactory();
// maximum size that will be stored in memory
factory.setSizeThreshold(maxMemSize);
// Location to save data that is larger than maxMemSize.
factory.setRepository(new File("c:\\temp"));
// Create a new file upload handler
ServletFileUpload upload = new ServletFileUpload(factory);
// maximum file size to be uploaded.
upload.setSizeMax(maxFileSize);
try{
// Parse the request to get file items.
List fileItems = upload.parseRequest(request);
// Process the uploaded file items
Iterator i = fileItems.iterator();
out.println("<html>");
out.println("<head>");
out.println("<title>Servlet upload</title>");
out.println("</head>");
out.println("<body>");
while (i.hasNext())
{
FileItem fi = (FileItem)i.next();
if (!fi.isFormField())
{
// Get the uploaded file parameters
String fieldName = fi.getFieldName();
String fileName = fi.getName();
String contentType = fi.getContentType();
boolean isInMemory = fi.isInMemory();
long sizeInBytes = fi.getSize();
// Write the file
if(fileName.lastIndexOf("\\") >= 0){
file = new File(filename +
fileName.substring(fileName.lastIndexOf("\\"))) ;
}else{
file = new File(filename +
fileName.substring(fileName.lastIndexOf("\\")+1)) ;
}
fi.write(file) ;
out.println("Uploaded Filename: " + fileName + "<br>");
System.out.println("Fichero "+filename+" subido correctamente al servidor!!");
}
}
out.println("</body>");
out.println("</html>");
}catch(Exception ex) {
System.out.println(ex);
}
}
但上傳後，這打開一個新的簡單的HTML，這是建立在以前的java方法out.println ...
關鍵是，我怎麼可以管理這個上傳留在相同的HTML知道是否文件已經上傳或者沒有這樣做我有這個文件的其他事情？我不能使用get方法來上傳文件，並讓表單動作變爲空白...
或者，打開一個新的html，必須有另一種方法來製作更復雜的html，而不是在Java函數中使用out.println ....
謝謝。
我想我需要用Javascript來上傳文件 –