更新多維數組

我有這樣的陣列，我試圖更新使用來自form.I發佈的數據更新多維數組

$arr = array(
    'one' => array(
    'slidertitle' => 'lorem ipsum', 
    'sliderlocation' => 'http://localhost/images/1.jpg', 
    'sliderdescription' => 'this is a good lorem ipsum image', 
    'sliderposition' => 1 
    ), 
    'two' => array(
    'slidertitle' => 'second slider', 
    'sliderlocation' => 'http://localhost/images/2.jpg', 
    'sliderdescription' => 'this space was reserved for a link source code here', 
    'sliderposition' => 2 
    ), 
    'three' => array(
    'slidertitle' => 'third slider', 
    'sliderlocation' => 'http://localhost/images/3.jpg', 
    'sliderdescription' => 'this is a third slider by name only', 
    'sliderposition' => 3 
    ), 
    'four' => array(
    'slidertitle' => 'fourth slider', 
    'sliderlocation' => 'http://localhost/images/4.jpg', 
    'sliderdescription' => 'fourth slider has a description', 
    'sliderposition' => 4 
    ), 
    'five' => array(
    'slidertitle' => 'fifth slider', 
    'sliderlocation' => 'http://localhost/images/5.jpg', 
    'sliderdescription' => 'a slider on rails is really nice', 
    'sliderposition' => 5 
    ), 
    'six' => array(
    'slidertitle' => 'sixth slider', 
    'sliderlocation' => 'http://localhost/images/6.jpg', 
    'sliderdescription' => 'this is the sixth slider,like,really!', 
    'sliderposition' => 6 
    ) 
);

沒有通過$ _ POST數據，因爲它只是一個例子消毒。

$clickedButton = $_POST['clickedButton']; 
$sliderKey = $_POST['sliderKey']; 
$sliderTitle = $_POST['sliderTitle']; 
$sliderDescription = $_POST['sliderDescription']; 
$sliderLocation = $_POST['sliderLocation']; 
$sliderPosition = $_POST['sliderPosition']; 
$result = mysql_query("SELECT * FROM arr"); 
$row = mysql_fetch_array($result); 
$data = $row['encoded_array']; 
//echo $data.'<br/>'.'<br/>'; 
$unserialized = unserialize($data); 
$unserialized[$sliderKey]["slidertitle"] = $sliderTitle; 
$unserialized[$sliderKey]["sliderlocation"] = $sliderLocation; 
$unserialized[$sliderKey]["sliderdescription"] = $sliderDescription; 
$unserialized[$sliderKey]["sliderposition"] = $sliderPosition; 
//print_r($unserialized); 
$newSerialize = serialize($unserialized); 
mysql_query("UPDATE arr SET encoded_array = '$newSerialize'");

當我print_r $unserialized，我剛纔發佈的數據是存在的，但沒有提交到數據庫，我serialize.Is有什麼我做錯了之後？

編輯：

我在陣列中的兩個記錄，這是我得到節省

a:2:{s:13:"5056d218631bc";a:4:{s:11:"slidertitle";s:5:"lorem";s:14:"sliderlocation";s:5:"ipsum";s:17:"sliderdescription";s:11:"hello world";s:14:"sliderposition";i:3;}s:13:"5056db269305c";a:4:{s:11:"slidertitle";s:1:"A";s:14:"sliderlocation";s:6:"RECORD";s:17:"sliderdescription";s:18:"WITH A DESCRIPTION";s:14:"sliderposition";s:1:"2";}}

系列化之前：

Array 
(
    [5056d218631bc] => Array 
     (
      [slidertitle] => lorem 
      [sliderlocation] => ipsum 
      [sliderdescription] => hello world 
      [sliderposition] => 3 
     ) 

    [5056db269305c] => Array 
     (
      [slidertitle] => A 
      [sliderlocation] => RECORD 
      [sliderdescription] => WITH A DESCRIPTION 
      [sliderposition] => 2 
     ) 

)

來源

2012-09-17 Gandalf

如果你在數據庫插入之前使用var_dump（$ newSerialize），你會得到什麼？ – JamesHalsall

我發佈的數據就在那裏。 – Gandalf

請不要使用'mysql_ *'函數，它已被棄用（請參閱[*紅盒子*]（http://php.net/manual/en/function.mysql-query.php）），並且容易受到sql注入。使用[* PDO *]（http://php.net/manual/en/book.pdo.php）或[* MySQLi *]（http://php.net/manual/en/book.mysqli.php）。 – alfasin

@alfasin @AdamGold @Poonam @ Jaitsu我真的值得每一點責備發佈這一點，但問題是，我失去了一個休息功能後，做了保存：

這是我

$x = $_POST['clickedButton']; 

switch ($x) 
{ 
case 'newSave': 
    newSave(); 
    break; 
case 'editSave': 
    editSave(); 
    ; 
case 'editDelete': 
    editDelete(); 
    ; 
    break; 
default: 
    echo "Some click"; 
}

有過這是我現在有工作

$x = $_POST['clickedButton']; 
//echo $x; 
switch ($x) 
{ 
case 'newSave': 
    newSave(); 
    break; 
case 'editSave': 
    editSave(); 
    ; 
    break; 
case 'editDelete': 
    editDelete(); 
    ; 
    break; 
default: 
    echo "Some click"; 
}

我感謝您的耐心和貢獻。

來源

2012-09-17 08:59:03 Gandalf

更新多維數組

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