在android中傳遞參數到url

Question

我正在開發一個涉及解析的android應用程序。我想在android中將參數傳遞給url。我應該如何繼續？

Answer 1

請試試這個。

HttpPost postMethod = new HttpPost("your url"); 
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); 

nameValuePairs.add(new BasicNameValuePair("your parameter","parameter value")); 
nameValuePairs.add(new BasicNameValuePair("your parameter","parameter value")); 

postMethod.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 
DefaultHttpClient hc = new DefaultHttpClient(); 

HttpResponse response = hc.execute(postMethod); 

nameValuePairs用於在url中添加參數。

Answer 2

這裏亞去（可與尋呼大）

public void Execute(final Request request,final ClientCallBackHandler CallBack) 
{ 
    new Thread(new Runnable(){ 
     @Override 
     public void run() { 

      HttpParams myParams = new BasicHttpParams(); 

      HttpConnectionParams.setConnectionTimeout(myParams, 10000); 
      HttpConnectionParams.setSoTimeout(myParams, 10000); 
      DefaultHttpClient httpClient = new DefaultHttpClient(myParams); 
     //dunno if this is correct... 
      if(CurrentConnection.SvUsr.length() > 0) 
      { 
       httpClient.getCredentialsProvider().setCredentials(
         new AuthScope(CurrentConnection.SvUrl, 80, null, "Digest"), 
         new UsernamePasswordCredentials(CurrentConnection.SvUsr, CurrentConnection.SvPw)); 
      } 
      HttpContext localContext = new BasicHttpContext(); 

      if(CurrentConnection != null) 
      { 




       HttpPost httpPost = new HttpPost(CurrentConnection.SvUrl); 
       try { 


        List<NameValuePair> pairs = new ArrayList<NameValuePair>(); 
        String blah = SerializeRequest(request); 
        pairs.add(new BasicNameValuePair("request",blah)); 

        httpPost.setEntity(new UrlEncodedFormEntity(pairs)); 

       } catch (UnsupportedEncodingException e) { 
        // TODO Auto-generated catch block 
        if(CallBack != null) 
        { 
         CallBack.SetStatus(ClientCallBackHandler.ENCODING_EXCEPTION); 
        } 

        return; 
       } 
       try { 
        if(CallBack != null) 
         CallBack.SetStatus(ClientCallBackHandler.HTTP_DID_START); 

        HttpResponse response = httpClient.execute(httpPost,localContext); 
        if(response != null) 
        { 
         if(CallBack != null) 
         { 
          CallBack.response = DeserializeResponse(EntityUtils.toString(response.getEntity())); 

          CallBack.SetStatus(ClientCallBackHandler.HTTP_DID_SUCCEED);         
         } 

         return; 
        } 
        else 
        { 
         if(CallBack != null) 
         { 
          CallBack.SetStatus(ClientCallBackHandler.HTTP_DID_ERROR); 
         } 

         return; 
        } 
       } catch (ClientProtocolException e) { 
        // TODO Auto-generated catch block 
        if(CallBack != null) 
        { 
         CallBack.SetStatus(ClientCallBackHandler.CLIENT_PROTOCOL_EXCEPTION); 
        } 

        e.printStackTrace(); 
        return; 
       } catch (IOException e) { 
        // TODO Auto-generated catch block 
        if(CallBack != null) 
        { 
         CallBack.SetStatus(ClientCallBackHandler.IO_EXCEPTION); 
        }      
        e.printStackTrace(); 
        return; 
       } 
      } 

     } 

    }).start(); 




} 

的SerializeRequest（）梅索德轉換的youre請求轉換成字符串的youre服務可以理解...例如我的是這樣看：

public String SerializeRequest(Request request) { 
    Gson gson = gsonb.create(); 
    String JScript = gson.toJson(request); 
    Log.v(request.getClass().getName(),JScript); 
    return JScript; 
} 

的DeserializeResponse（）梅索德確實的此幾乎相反的，所以在GSON的情況下：

public Response DeserializeResponse(String Jscript) 
{ 
    Response response = null; 

    try { 

     JSONObject jsonObject = new JSONObject(Jscript); 

     Gson gson = gsonb.create(); 
     response = gson.fromJson(jsonObject.toString(), Response.class); 
       if(response.ClassName.compareTo("ExceptionResponse")==0) 
      response = gson.fromJson(jsonObject.toString(), ExceptionResponse.class);   
    } catch (JSONException e) { 
     // TODO Auto-generated catch block 
     response = new ExceptionResponse(); 
     ((ExceptionResponse) response).Message = Jscript; 
    } 
    Log.v(response.getClass().getName(),Jscript); 
    return response; 
} 

Answer 3

private void postData(final String param, final TextView tv) { 

     RequestQueue rq = Volley.newRequestQueue(this); 

     StringRequest postReq = new StringRequest(Request.Method.POST, 
       "https://your URL", 
       new Response.Listener<String>() { 

        @Override 
        public void onResponse(String response) { 
         tv.setText(response); // We set the response data in the 
               // TextView 
         Toast.makeText(getApplicationContext(), "Response"+response,Toast.LENGTH_LONG).show(); 
        } 
       }, new Response.ErrorListener() { 

        @Override 
        public void onErrorResponse(VolleyError error) { 
         System.out.println("Error [" + error + "]"); 

         Toast.makeText(getApplicationContext(), "No Internet!!!", Toast.LENGTH_LONG).show(); 

        } 
       }) { 

      @Override 
      protected Map<String, String> getParams() throws AuthFailureError { 
       Map<String, String> params = new HashMap<String, String>(); 

       params.put("your key", "value"); 
       params.put("any callback methods", "value"); 
       params.put("any types", "value"); 
       return params; 
      } 

     }; 

     rq.add(postReq);