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在PHP中有經驗,但對jQuery來說是新的:我想用ajax從json編碼的php文件中獲取數據來填充簡單的數據表。PHP:提供用於填充數據表的JSON
table.php
:HTML代碼段
<head>...
<script type="text/javascript" charset="utf-8">
$(document).ready(function() {
$('#example').dataTable({
"bProcessing": true,
"sAjaxSource": 'deliver_tests.php',
"sScrollY": "200px",
"bPaginate": false
});
});
</script>
</head>
<body> ...
<div id="demo">
<table cellpadding="0" cellspacing="0" border="0" class="display" id="example" width="100%">
<thead>
<tr>
<th>id</th>
<th>Status</th>
<th>Abkürzung</th>
<th>Test</th>
<th>Patient</th>
<th>Datum</th>
</tr>
</thead>
<tbody></tbody>
</table>
</div>
deliver_tests.php
:代碼片段:
try {
$sql = "SELECT tsID, tsStatus, tbShortname, tbName, paCode, tsCompleted_Date FROM test LEFT JOIN testbase ON tsTestBaseID = tbID LEFT JOIN patient ON tsPatientID = paID WHERE tsAccountID=:accID ORDER BY tsCompleted_Date DESC";
$dbTests = $objDB->prepare($sql);
$bind=array('accID' => $_SESSION['aID']);
$dbTests->execute($bind);
$tests = $dbTests->fetchAll(PDO::FETCH_ASSOC);
} catch (PDOException $dbe) {
// error
}
$tests = array('aaData' => $tests);
echo json_encode($tests);
看到它的輸出這裏:http://pastebin.com/uZiLepSb
調用table.php
,我得到一個JS-警報:
DataTables warning (table id = 'example'):
Requested unknown parameter '0' from the data source for row 0
我想我必須要重構的數組?
我需要提示如何從這裏繼續 - 提前謝謝!
是的!這就是訣竅! – michi