獲取_id並顯示新添加的聯繫人的姓名：min API 7

Question

在我的應用程序中，我實現了添加聯繫人的功能。爲此我使用的代碼

Intent addNewContact = new Intent(Intent.ACTION_INSERT); 
addNewContact.setType(ContactsContract.Contacts.CONTENT_TYPE); 
startActivityForResult(addNewContact, ADD_NEW_CONTACT); 

增加接觸（在活動結果）後，我想證明接觸（只，我不想重複URI），但我不知道如何只顯示該聯繫人。有沒有辦法？

這裏是我的onActivityResult（）

protected void onActivityResult(int requestCode, int resultCode, Intent data) { 
     if (requestCode == ADD_NEW_CONTACT) { 
      if(resultCode == -1) { 
       Log.i("New contact Added : ", "Addedd new contact, Need to refress item list"); 
      } else { 
       Log.i("New contact Added : ", "Canceled to adding new contacts : Not need to update item list"); 
      } 
     } 
    } 

謝謝！

Answer 1

您必須閱讀data參數onActivityResult()，您可以在其中得到_id，顯示名等。

試試這個代碼

protected void onActivityResult(int requestCode, int resultCode, Intent data) { 
     if (requestCode == ADD_NEW_CONTACT) { 
      if(resultCode == -1) { 
       Uri contactData = data.getData(); 
        Cursor cursor = managedQuery(contactData, null, null, null, null); 
        if (cursor.moveToFirst()) { 
         long newId = cursor.getLong(cursor.getColumnIndexOrThrow(Contacts._ID)); 
         String name = cursor.getString(cursor.getColumnIndexOrThrow(Contacts.DISPLAY_NAME)); 
         Log.i("New contact Added", "ID of newly added contact is : " + newId + " Name is : " + name); 
        } 
       Log.i("New contact Added : ", "Addedd new contact, Need to refress item list : DATA = " + data.toString()); 
      } else { 
       Log.i("New contact Added : ", "Canceled to adding new contacts : Not need to update database"); 
      } 
     } 
    } 

編碼愉快。