遍歷內嵌套的對象

這是我的目標：遍歷內嵌套的對象

family_Data = { 
    "Family": [ 
     { 
      "id": "Family-15", 
      "members": 
      { 
       "Family-15-01": [{"Family Code": "Family-15-01","Gender": "Female", "Full Name" : "Evelyn Osei"}], 
       "Family-15-02": [{"Family Code": "Family-15-02","Gender": "Male", "Full Name" : "David Will"}], 
       "Family-15-03": [{"Family Code": "Family-15-03","Gender": "Male", "Full Name" : "Edwin Pan"}] 
      } 
     } 
    ] 
}

我想遍歷「成員」的對象。

來源

2016-12-28 Drew

瑣碎的使用嵌套的'$ .each'，但你嘗試過什麼？ –

提示：'family_Data.Family [0] .members'指的是你想循環的對象。 –

您可以使用'for（var key in family_Data.Family [0] .members）'循環獲取所有鍵的對象 – VadimB

var family_Data = { 
 
"Family": [ 
 
{ 
 
"id": "Family-15", 
 
"members": { 
 
"Family-15-01": [{"Family Code": "Family-15-01","Gender": "Female", "Full Name" : "Evelyn Osei"}], 
 
"Family-15-02": [{"Family Code": "Family-15-02","Gender": "Male", "Full Name" : "David Will"}], 
 
"Family-15-03": [{"Family Code": "Family-15-03","Gender": "Male", "Full Name" : "Edwin Pan"}] 
 
} 
 
} 
 
] 
 
}; 
 
for(var key in family_Data.Family[0].members){ 
 
    console.log(family_Data.Family[0].members[key]); 
 
    }

來源

2016-12-28 16:14:01

太棒了！非常感謝。 – Drew

首先得到您的members對象。

var members = family_Data.Family[0].members;

然後遍歷該對象。

for(var key in members){ 
    var member = members[key]; 
    // here we go. 
}

來源

2016-12-28 16:13:19 subash

Subash，您的代碼可以正常工作，但是您可以幫助我刪除Family代碼。我想要這樣的對象：「成員」：{{「家庭代碼」：「家庭15-01」，「性別」：「女性」，「全名」：「Evelyn Osei」}]， [ {「家庭代碼」：「家庭15-02」，「性別」：「男性」，「全名」：「大衛威爾」}]， [{「家庭代碼」：「家庭15-03」，「性別」：「男性」，「全名」：「Edwin Pan」}] } – Drew

我已將自己排序爲Subash。這就是我所做的。 var result = {}; member.forEach（x => {x.que] = x.ans; }）; – Drew

遍歷內嵌套的對象

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