如何把列表視圖中viewpager

Question

我的工作簡單的應用程序，我做了3次一viewpager，我需要把列表視圖中viepager 但列表視圖不會showup 這裏是我的viewpager 包特級com.Schoolreporting.androidApp;

import java.util.ArrayList; 

import android.content.Context; 
import android.location.Address; 
import android.os.Parcelable; 
import android.support.v4.view.PagerAdapter; 
import android.support.v4.view.ViewPager; 
import android.view.View; 
import android.widget.Adapter; 
import android.widget.ArrayAdapter; 
import android.widget.LinearLayout; 
import android.widget.ListAdapter; 
import android.widget.ListView; 
import android.widget.TextView; 
import android.widget.Toast; 

    public class MyPagerAdapter extends PagerAdapter { 
String Name; 


// State number of pages 
public int getCount() { 
    return 4; 
} 

public void setName(String Name) { 
    this.Name = Name; 
} 


// Set each screen's content 
@Override 
public Object instantiateItem(View container, int position) { 
    Context context = container.getContext(); 
    LinearLayout layout = new LinearLayout(context); 

    // Add elements 
    TextView textItem = new TextView(context); 
    ListView grades=new ListView(context); 
    ArrayList<String>names=new ArrayList<String>(); 
    names.add("Adel"); 
    names.add("zetta"); 
    names.add("Pringy"); 

    ArrayAdapter<String> adapter=new ArrayAdapter<String>  (context,android.R.layout.simple_list_item_1,names); 
    grades.setAdapter(adapter); 
    switch (position) { 
    case 0: 


     Toast.makeText(context,names.get(1),Toast.LENGTH_LONG).show(); 
     textItem.setText(Name + "'s Grades"); 


     grades.setAdapter(adapter); 
     Toast.makeText(context,names.get(1),Toast.LENGTH_LONG).show(); 
     break; 
    case 1: 
     grades.setAdapter(adapter); 

     textItem.setText(Name + "'s grades"); 

     break; 
    case 2: 

     textItem.setText(Name + "'s feedback"); 


     break; 
    case 3: 

     textItem.setText(Name + "'s school"); 


     break; 

    } 
    layout.addView(textItem); 
    ((ViewPager) container).addView(layout, 0); // This is the line I 
               // added 
    return layout; 
} 

@Override 
public void destroyItem(View arg0, int arg1, Object arg2) { 
    ((ViewPager) arg0).removeView((View) arg2); 
} 

@Override 
public boolean isViewFromObject(View arg0, Object arg1) { 
    return arg0 == ((View) arg1); 
} 

@Override 
public Parcelable saveState() { 
    return null; 
} 

} 

Answer 1

你可以這樣做，用下面的代碼：

Context context; 
List<View> viewList; 

public MyPagerAdapter(Context context) { 
    this.context = context; 
    viewList = new ArrayList<View>(); 
    LayoutInflater inflater = LayoutInflater.from(context); 
    View pg1 = inflater.inflate(R.layout.pg1_layout, null); 
    View pg2 = inflater.inflate(R.layout.pg2_layout, null); 
    View pg3 = inflater.inflate(R.layout.pg3_layout, null); 
    viewList.add(pg1); 
    viewList.add(pg2); 
    viewList.add(pg3); 
}