,所以我想創建一個PHP MySQL的聊天,我在一個頁面上,但在實際的聊天具有的JavaScript load()成功頁,我不能得到它的工作B/C每個聊天有聊天ID(ch_id)附加到URL(所以它看起來像chats.php?ch_id =#)...當我嘗試和自動刷新聊天窗口加載(),它不會帶來聊天ID,所以頁面刷新爲空白。有什麼想法嗎?PHP的MySQL聊天自動加載不工作B/C不能得到得到聊天ID
CODE:HTML
<div id="load_chat">
<?php include('load_chat.php'); ?>
</div>
PHP - load_chat.php文件
<div class="scroller" style="height: 525px;" data-always-visible="1" data-rail-visible1="1">
<ul class="chats">
<?php
$chat = "SELECT * FROM chats WHERE ch_id = '".$ch_id."'";
$r_ch = mysqli_query($con, $chat);
$w_ch = mysqli_fetch_array($r_ch);
$get_chat = "SELECT * FROM chat_log WHERE ch_id = '".$ch_id."'";
$run_chat = mysqli_query($con, $get_chat);
while($row_chat = mysqli_fetch_array($run_chat)) {
$get_sender = "SELECT * FROM users WHERE u_id = '".$row_chat['u_id']."'";
$run_sender = mysqli_query($con, $get_sender);
$row_sender = mysqli_fetch_array($run_sender);
$get_rec = "SELECT * FROM users WHERE u_id = '".$row_chat['r_id']."'";
$run_rec = mysqli_query($con, $get_rec);
$row_rec = mysqli_fetch_array($run_rec);
?>
<li class='in'>
<img class='avatar' alt='' src='images/<?php echo "".$row_sender['u_img'].""; ?>' />
<div class='message'>
<a href='javascript:;' class='name'> <?php echo "".$row_sender['u_fn']." ".$row_sender['u_ln'].""; ?> </a>
<span class='datetime'> <?php echo "".date("g:i a", strtotime($row_chat['chat_sent'])).""; ?> </span>
<span class='body'> <?php echo "".$row_chat['c_cont'].""; ?> </span>
</div>
</li>
<?php
}
?>
</ul>
</div>
JAVASCRIPT
<script>setInterval(function() { ('#load_chat').load('load_chat.php'); }, 2000)</script>
澄清......在「().load()函數工作......但是當它刷新時,它正在丟失聊天ID(.com?ch_id =#上的URL)......我想我的主要問題,有沒有辦法通過e聊天ID到子文件夾/文件?該頁面刷新特定頁面(當一個新的聊天組被啓動時,一個文件被創建,其中包含php/mysql查詢以獲取所有記錄的聊天記錄),並且我需要將聊天ID傳遞給這些頁面...我如何去做?
謝謝你爲大家誰在...已經插話說我真的很感激所有幫助我從這個社區得到!
是您的示例JavaScript正是你在你的應用?因爲如果是的話,(我假設的jQuery這裏),你想將其更改爲' ',你錯過了美元符號。 –