在foreach循環中計算strpos適用次數

Question

如何顯示在循環中顯示sence的次數？

$i = 0; 
foreach ($parts as $new[$i]) { 

    $abouttoexpire = strpos($new[$i], 'Your Airbnb question is about to expire'); 
    $anairbnbexpert = strpos($new[$i], 'An Airbnb expert is waiting on feedback from you regarding'); 
    $requesttoalter = strpos($new[$i], 'Your request to alter reservation'); 

    //when the message was made 
    preg_match('/<div class="timestamp"[\s\S]*?>(.*)*?\+0000<\/div>/', $new[$i], $dateofmsg); 

    //between 9am and 6pm 
    $hour = date('H', strtotime(@$dateofmsg[1])); 
    if ($hour >= 9 && $hour <= 18) { 

     //if we found this sentence 
     if ($abouttoexpire !== FALSE) { 
     //how i show here how many times we catch the sentence @abouttoexpire?? 
     } 
    } 
} 
$i++; 

裏面的條件：if ($abouttoexpire !== FALSE) 如何打印此SENCE（@abouttoexpire）的時間循環期間計提壞賬？

Answer 1

$i = 0;$j=0; 
foreach ($parts as $new[$i]) { 

    $abouttoexpire = strpos($new[$i], 'Your Airbnb question is about to expire'); 
    $anairbnbexpert = strpos($new[$i], 'An Airbnb expert is waiting on feedback from you regarding'); 
    $requesttoalter = strpos($new[$i], 'Your request to alter reservation'); 

    //when the message was made 
    preg_match('/<div class="timestamp"[\s\S]*?>(.*)*?\+0000<\/div>/', $new[$i], $dateofmsg); 

    //between 9am and 6pm 
    $hour = date('H', strtotime(@$dateofmsg[1])); 
    if ($hour >= 9 && $hour <= 18) { 

    //if we found this sentence 
    if ($abouttoexpire !== FALSE) { 
     $j++; 
    } 
    } 

} 
$i++; 

echo 'no_of_times:'.$j; 

Answer 2

嘗試......

$i = 0; 
    $j = 0; 
    $k = 0; 
    foreach ($parts as $new[$i]) { 

    if ($hour >= 9 && $hour <= 18) { 

    $j++; 

    if ($abouttoexpire !== FALSE) { 

    $k++; 

     } 
    } 
    $i++; 
    } 

    echo "foreach loop=".$i; 
    echo "if loop =".$j; 
    echo "within if loop =".$k;