Codeigniter多維數組到數據庫

Question

我試圖將數組作爲單獨的行插入到數據庫表中。該數組是從用戶可以添加其他行的表中生成的。無法解決問題！

下面是這個視圖

<table class="table table-bordered" id="parts"> 
    <thead class="table-success"> 
    <tr> 
     <th class="table-success">Quantity</th> 
     <th class="table-success">Parts</th> 
     <th class="table-success">Fitted</th> 
     <th class="table-success">Required</th> 
     <th class="table-success">Cost</th> 
    </tr> 
    </thead> 
    <tbody> 
    <tr> 
     <input type="hidden" name="job_no[]" value="<?php echo $job_number; ?>" /> 
     <td><input type="number" name="parts_qty[]" class="form-control" /></td> 
     <td><input type="text" name="parts_description[]" class="form-control" /></td> 
     <td><input type="text" name="parts_fitted[]" class="form-control" /></td> 
     <td><input type="text" name="parts_required[]" class="form-control" /></td> 
     <td><input type="text" name="parts_cost[]" class="form-control" /></td> 
    </tr> 
    </tbody> 
</table> 
<button type="button" class="btn btn-primary btn-xs" id="addRow"> <span class="glyphicon glyphicon-plus-sign" aria-hidden="true"> </span> Add Row </button> 
<script> 
$(document).ready(function() { 
    $("#addRow").click(function(){ 
      $("#parts").append("<tr><input type='hidden' name='job_no[]' value='<?php echo $job_number; ?>' /><td><input type='number' name='parts_qty[]' class='form-control' /></td><td><input type='text' name='parts_description[]' class='form-control' /></td><td><input type='text' name='parts_fitted[]' class='form-control' /></td><td><input type='text' name='parts_required[]' class='form-control' /></td><td><input type='text' name='parts_cost[]' class='form-control' /></td></tr>"); 
     }); 
    }); 
</script> 

請注意，這是一個更大形式的一部分，因此沒有顯示提交按鈕等

我的控制器功能看起來像這樣

function add_parts_db() 
    { 
     $parts = array (
        'job_number' => $this->input->post('job_no'), 
        'quantity'  => $this->input->post('parts_qty'), 
        'parts'   => $this->input->post('parts_description'), 
        'fitted'  => $this->input->post('parts_fitted'), 
        'required'  => $this->input->post('parts_required'), 
        'cost'   => $this->input->post('parts_cost') 
       ); 

       $this->service_model->add_parts_db($parts); 
       redirect('service', 'refresh'); 
    } 

這裏該陣列通過表格中的一些樣本輸入生成

Array 
(
    [job_number] => Array 
     (
      [0] => 2008 
      [1] => 2008 
      [2] => 2008 
     ) 

    [quantity] => Array 
     (
      [0] => 1 
      [1] => 2 
      [2] => 3 
     ) 

    [parts] => Array 
     (
      [0] => Part 1 
      [1] => Part 2 
      [2] => Parts 3 
     ) 

    [fitted] => Array 
     (
      [0] => Fitted 1 
      [1] => Fitted 1 
      [2] => Fitted 3 
     ) 

    [required] => Array 
     (
      [0] => Required 1 
      [1] => Required 2 
      [2] => Required 3 
     ) 

    [cost] => Array 
     (
      [0] => 1.00 
      [1] => 2.00 
      [2] => 3.00 
     ) 

) 

最後我希望將數組的每個項插入到數據庫表中作爲單獨的行。

function add_parts_db($parts) 
{ 
    $this->db->insert_batch('parts', $parts); 
    return $this->db->insert_id(); 
} 

我想上面的陣列被插入到數據庫中作爲單獨的行所以應該是這個樣子

提交表單

的時候，我發現了以下錯誤

Error Number: 1064 

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '0, 1, 2) VALUES ('2008','2008','2008'), ('1','2','3'), ('Part 1','Part 2','Parts' at line 1 

INSERT INTO `parts` (0, 1, 2) VALUES ('2008','2008','2008'), ('1','2','3'), ('Part 1','Part 2','Parts 3'), ('Fitted 1','Fitted 1','Fitted 3'), ('Required 1','Required 2','Required 3'), ('1.00','2.00','3.00') 

Filename: models/Service_model.php 

Line Number: 33 

我認爲這個問題可能出在我的jQuery/Javascript中，我不太明白。我可以使用名稱設置初始密鑰爲0 =「配件[0] [jobnumber可以]」但後來在我的jQuery的，我不認爲這是識別變量正確

var $i = 1; 
     $("#addRow").click(function(){ 
       $("#parts").append("<tr><input type='hidden' name='parts[$i][jobnumber]' value='<?php echo $job_number; ?>' /><td><input type='number' name='parts[$i][qty]' class='form-control' /></td><td><input type='text' name='parts[$i][description]' class='form-control' /></td><td><input type='text' name='parts[i][fitted]' class='form-control' /></td><td><input type='text' name='parts[$i][required]' class='form-control' /></td><td><input type='text' name='parts[$i][cost]' class='form-control' /></td></tr>"); 
       i++; 
     }); 

我認爲傾銷陣列看起來像它的去拉正確的數組格式，但它沒有得到它，因爲我的無能的jQuery。

["parts"]=> 
    array(2) { 
    [0]=> 
    array(5) { 
     ["jobnumber"]=> 
     string(4) "2002" 
     ["qty"]=> 
     string(1) "3" 
     ["description"]=> 
     string(7) "parts 3" 
     ["required"]=> 
     string(10) "required 3" 
     ["cost"]=> 
     string(4) "3.00" 
    } 
    ["i"]=> 
    array(1) { 
     ["fitted"]=> 
     string(8) "fitted 3" 
    } 
    } 

這是顯示一個語法錯誤，如果我與第二回復去

@Bhaumik梅塔

Array 
    (
     [0] => Array 
      (
       [job_number] => 2002 
       [quantity] => 1 
       [parts] => parts 1 
       [fitted] => Fitted 1 
       [required] => Required 1 
       [cost] => 1.00 
      ) 

     [1] => Array 
      (
       [job_number] => 2002 
       [quantity] => 2 
       [parts] => Part 2 
       [fitted] => Fitted 2 
       [required] => Required 2 
       [cost] => 2.00 
      ) 

     [2] => Array 
      (
       [job_number] => 2002 
       [quantity] => 3 
       [parts] => Parts 3 
       [fitted] => Fitted 3 
       [required] => Required 3 
       [cost] => 3.00 
      ) 

    ) 

Answer 1

你正在構建你的陣列的方式是錯誤的，你想什麼要做什麼，因爲每個數據庫列都有一個數組，並且您想要的是每個數據庫行的數組。

取而代之的是，你的部分描述添加到一個數組

<td><input type="text" name="parts_description[]" class="form-control" /></td> 

你需要的東西是這樣的：第一行

<td><input type="text" name="job[$i][parts_description]" class="form-control" /></td> 

凡$i=0，然後通過增加它1，每個新行由你的jQuery函數添加。

這樣，您將結束與包含與對應的單排每一個你的桌子上，然後可以循環到插入到數據庫

Answer 2

這雖然這種解決方案可能會來方便多陣列$_POST['job']變量。這不是理想的解決方案。

function add_parts_db() 
    { 
     $parts = array (
        'job_number' => $this->input->post('job_no'), 
        'quantity'  => $this->input->post('parts_qty'), 
        'parts'   => $this->input->post('parts_description'), 
        'fitted'  => $this->input->post('parts_fitted'), 
        'required'  => $this->input->post('parts_required'), 
        'cost'   => $this->input->post('parts_cost') 
       ); 

      $partsArr = []; 
      $totalCnt = count($parts['job_number']); 
      for($key=0; $key < $totalCnt ;$key++) 
      { 
      $partsArr[] = [ 
       'job_number' => $parts['job_number'][$key] , 
       'quantity' => $parts['quantity'][$key] , 
       'parts'  => $parts['parts'][$key] , 
       'fitted'  => $parts['fitted'][$key] , 
       'required' => $parts['required'][$key] , 
       'cost'  => $parts['cost'][$key]]; 

      } 
      //just make sure that your service_model uses `insert_batch` method to insert data 
      $this->service_model->add_parts_db($partsArr); 
      redirect('service', 'refresh'); 
    } 

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