Tkinter filedialog.askopenfilename中的例外

Question

我嘗試在使用此代碼的終端中打開pdf文件並打印文件名。

from Tkinter import * 
# Hold onto a global reference for the root window 
root = None 
filename = '' 

def openFile(): 
    global filename 
    root.filename = root.filedialog.askopenfilename(filetypes = (("PDF File" , "*.pdf"),("All Files","*.*"))) 
    print root.filename 

def main(): 
    global root 
    root = Tk() # Create the root (base) window where all widgets go 
    openButton = Button(root, text="Genarate",command=openFile) 
    openButton.pack() 
    root.mainloop() # Start the event loop 


main() 

但是，代碼是不正確的工作。當我按Genarate按鈕給這個錯誤。

Exception in Tkinter callback 
Traceback (most recent call last): 
    File "/usr/lib/python2.7/lib-tk/Tkinter.py", line 1540, in __call__ 
    return self.func(*args) 
    File "1gui.py", line 12, in openFile 
    root.filename = root.filedialog.askopenfilename(filetypes = (("PDF File" , "*.pdf"),("All Files","*.*"))) 
    File "/usr/lib/python2.7/lib-tk/Tkinter.py", line 1902, in __getattr__ 
    return getattr(self.tk, attr) 
AttributeError: filedialog 

我的代碼有什麼問題？

Answer 1

Tk主窗口爲無屬性filedialog.askopenfilename，您必須從tkFileDialog模塊導入askopenfilename。

# python2 
from Tkinter import * 
from tkFileDialog import askopenfilename 
# Hold onto a global reference for the root window 
root = None 
filename = '' 

def openFile(): 
    global filename 
    filename = askopenfilename(filetypes = (("PDF File" , "*.pdf"),("All Files","*.*"))) 
    print filename 

def main(): 
    global root 
    root = Tk() # Create the root (base) window where all widgets go 
    openButton = Button(root, text="Genarate",command=openFile) 
    openButton.pack() 
    root.mainloop() # Start the event loop 

main() 

備註：與python3進口將

from tkinter import * 
from tkinter.filedialog import askopenfilename