2016-07-25 11 views
1

這裏是我的JSON,我已經從一個簡單的谷歌搜索阿比我 要收集拿到第一個URL(https://www.facebook.com/Rashtriye-Goraksha-Sena-Appeal-Pls-Save-Mother-Cow-149271605156819/) 不要問我爲什麼那第一個鏈接,牛請笑在我的谷歌搜索的API調用,它返回一個有效的JSON,但每當我分析它得到一個特定的值,我得到了一個未定義

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} 

隨着下面的代碼

result=JSON.parse(body); 
callback(result); 
console.log(result); 

它將返回給我一個有效的JSON 我得到前面提到的JSON a第二它一切運作良好

不幸的是,我不想的JSON ......我只是想第一URL

我已經試過

console.log(result.items.link) 
console.log(result.items.0.link) 
console.log(result.items."0".link) 

這些都不版本。 是我的JSON分析器錯了嗎?

回答

1

你想幹什麼

result.items[0].link 

result.items是一個數組。要訪問您必須使用方括號的數組的第一個元素。

+0

你是一個生命的救星......這也正是它 –

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