在c＃中創建一個datagridview窗體＃

Question

我對c＃和windows窗體應用程序很陌生。 現在，我想在我的表單中創建一個Datagridview，其行數要填充業務對象的屬性。我遵循這個msdn頁面中的示例：How to: Bind Objects to Windows Forms DataGridView Controls並創建了我自己的程序，但是沒有像在msdn示例中那樣得到類似的結果，而是得到了一個包含三個空行的datagridview。我究竟做錯了什麼？下面是我的程序：

using System; 
using System.Windows.Forms; 


public class Form3 : Form 
{ 
    private DataGridView dataGridView1 = new DataGridView(); 
    private BindingSource bindingSource1 = new BindingSource(); 

    public Form3() 
    {    
     this.Load += new System.EventHandler(EnumsAndComboBox_Load); 
    } 

    private void EnumsAndComboBox_Load(object sender, System.EventArgs e) 
    { 
     // Populate the data source.   
     bindingSource1.Add(new Test("bli", "bla", "blop", "ha", "ho", "he")); 
     bindingSource1.Add(new Test("bli", "bla", "blop", "ha", "ho", "he")); 

     // Initialize the DataGridView. 
     dataGridView1.AutoGenerateColumns = false; 
     dataGridView1.AutoSize = true; 
     dataGridView1.DataSource = bindingSource1; 

     // Initialize and add a text box column. 
     DataGridViewColumn column = new DataGridViewTextBoxColumn(); 
     column.DataPropertyName = "Name1"; 
     column.Name = "Name1"; 
     dataGridView1.Columns.Add(column); 

     // Initialize and add a check box column. 
     column = new DataGridViewTextBoxColumn(); 
     column.DataPropertyName = "Name2"; 
     column.Name = "Name2"; 
     dataGridView1.Columns.Add(column); 

     column = new DataGridViewTextBoxColumn(); 
     column.DataPropertyName = "Name3"; 
     column.Name = "Name3"; 
     dataGridView1.Columns.Add(column); 

     column = new DataGridViewTextBoxColumn(); 
     column.DataPropertyName = "Name4"; 
     column.Name = "Name4"; 
     dataGridView1.Columns.Add(column); 

     column = new DataGridViewTextBoxColumn(); 
     column.DataPropertyName = "Name5"; 
     column.Name = "Name5"; 
     dataGridView1.Columns.Add(column); 

     column = new DataGridViewTextBoxColumn(); 
     column.DataPropertyName = "Name6"; 
     column.Name = "Name6"; 
     dataGridView1.Columns.Add(column); 

     // Initialize the form. 
     this.Controls.Add(dataGridView1); 
     this.AutoSize = true; 
     this.Text = "DataGridView object binding demo"; 
    } 

    #region "test object" 
    private class Test 
    { 
     private string test1; 
     private string test2; 
     private string test3; 
     private string test4; 
     private string test5; 
     private string test6; 

     public Test(string s1, string s2, string s3, string s4, string s5, string s6) 
     { 
      test1 = s1; 
      test2 = s2; 
      test3 = s3; 
      test4 = s4; 
      test5 = s5; 
      test6 = s6; 
     } 

     public Test() 
     { 
      test1 = "bla"; 
      test2 = "bla"; 
      test3 = "bla"; 
      test4 = "bla"; 
      test5 = "bla"; 
      test6 = "bla"; 
     } 


     public string Test1 
     { 
      get 
      { 
       return test1; 
      } 
      set 
      { 
       test1 = value; 
      } 
     } 

     public string Test2 
     { 
      get 
      { 
       return test2; 
      } 
      set 
      { 
       test2 = value; 
      } 
     } 

     public string Test3 
     { 
      get 
      { 
       return test3; 
      } 
      set 
      { 
       test3 = value; 
      } 
     } 

     public string Test4 
     { 
      get 
      { 
       return test4; 
      } 
      set 
      { 
       test4 = value; 
      } 
     } 

     public string Test5 
     { 
      get 
      { 
       return test5; 
      } 
      set 
      { 
       test5 = value; 
      } 
     } 

     public string Test6 
     { 
      get 
      { 
       return test6; 
      } 
      set 
      { 
       test6 = value; 
      } 
     } 
    } 

    #endregion 

    static class Program 
    { 
     [STAThread] 
     public static void Main() 
     { 
      Application.Run(new Form3()); 
     } 
    } 
} 

Answer 1

要綁定列的屬性稱爲1 Name到6，但在你的對象沒有這樣的特性。將Name更改爲Test。即

從這個：

column = new DataGridViewTextBoxColumn(); 
column.DataPropertyName = "Name6"; 
column.Name = "Name6"; 
dataGridView1.Columns.Add(column); 

這樣：

column = new DataGridViewTextBoxColumn(); 
column.DataPropertyName = "Test6"; 
column.Name = "Name6"; 
dataGridView1.Columns.Add(column); 

也通過建議@noobob您

dataGridView1.DataSource = bindingSource1; 

移到方法

Answer 2

結束「 DataPropertyName「屬性的每個col umn必須與正在評估的數據對象的屬性名稱匹配。所以，如果你只是做出這樣一個微小的變化：

column.DataPropertyName = "Test1"; 

一切都應該工作。

Answer 3

column.DataPropertyName應該設置爲您在數據源類中指定的屬性名稱。嘗試此：

column = new DataGridViewTextBoxColumn(); 
    column.DataPropertyName = "Test1"; 
    column.Name = "Test1"; 
    dataGridView1.Columns.Add(column); 

    column = new DataGridViewTextBoxColumn(); 
    column.DataPropertyName = "Test2"; 
    column.Name = "Test2"; 
    dataGridView1.Columns.Add(column); 

    column = new DataGridViewTextBoxColumn(); 
    column.DataPropertyName = "Test3"; 
    column.Name = "Test3"; 
    dataGridView1.Columns.Add(column);