腓的foreach in_array保持返回false

Question

我建造了遍歷一個特定的文件夾，並得到一個數組的foreach：

foreach ($watchFolder as $key => $value) { 
    echo '<pre>'; 
    print_r($value); 
    echo '</pre>'; 
    if((in_array('xml', $watchFolder))) { 
    echo "true"; 
    } else { 
    echo "false"; 
    } 

    foreach ($value as $key => $valueSub) { 
    $currentWatchPath2 = $currentWatchPath . '\\' . $key; 
    foreach ($valueSub as $content) { 
     $currentWatchPath3 = $currentWatchPath2 . '\\' . $content; 
    } 
    } 
} 

如果我打印出來的$watchfolder我得到這個：

Array (
    [test] => Array([videos] => Array() 
        [xml] => Array()) 

    [test2] => Array([json] => Array([0] => test.json) 
        [videos] => Array()) 
) 

如果我試試這個：

它返回null，而它應該返回真的還是？

我現在很困惑，所以我很感激每一個提示和建議。

Answer 1

xml是$value陣列的關鍵，所以我覺得你應該檢查是這樣的：

foreach ($watchFolder as $key => $value) { 
     echo '<pre>'; 
     print_r($value); 
     echo '</pre>'; 
     if(isset($value['xml'])) { // <--- here is the changed. 
      echo "true"; 
     } else { 
      echo "false"; 
     } 

     foreach ($value as $key => $valueSub) { 

      $currentWatchPath2 = $currentWatchPath . '\\' . $key; 

      foreach ($valueSub as $content) { 

       $currentWatchPath3 = $currentWatchPath2 . '\\' . $content; 

      } 

     } 

    } 

Answer 2

在in_array（ 'XML'，$ watchFolder）的更換，就可以使用in_array（ 'XML'， $ value）

foreach ($watchFolder as $key => $value) { 
    echo '<pre>'; 
    print_r($value); 
    echo '</pre>'; 
    if((in_array('xml', $value))) { 
     echo "true"; 
    } else { 
     echo "false"; 
    } 

    foreach ($value as $key => $valueSub) { 

     $currentWatchPath2 = $currentWatchPath . '\\' . $key; 

     foreach ($valueSub as $content) { 

      $currentWatchPath3 = $currentWatchPath2 . '\\' . $content; 

     } 

    } 

}