將羅馬數字轉換爲十進制

Question

嘿，我認爲我很親密，但我不太確定如何繼續。所有與我的問題有關的問題都沒有真正回答。那我得到現在的錯誤是

(33): error C2064: term does not evaluate to a function taking 1 arguments 
(41): error C2064: term does not evaluate to a function taking 1 arguments 

頭文件：

using namespace std; 

class romanType 
{ 
public: 
    void printRoman(char romanNum); 
    int printDecimal(int& total); 
    int convertRoman(int& total); 
    void setRoman(char& roman); 

    romanType(); 
    romanType(char); 

private: 
    char romanNum[6]; 
    int decimal; 
    int total; 
}; 

實現：

#include "stdafx.h" 
#include <iostream> 
#include <iomanip> 
#include "romanType.h" 

using namespace std; 

romanType::romanType(char) 
{ 

}; 
void romanType::printRoman(char romanNum) 
{ 
    cout << "Here is your number in Roman Numeral form: " << romanNum << endl; 
}; 

int romanType::printDecimal(int& total) 
{ 
    cout << "Here is your number in Decimal form: " << total << endl; 
    return total; 
}; 

void romanType::setRoman(char& romanNum) 
{ 

}; 
int romanType::convertRoman(int& total) 
{ 
    int len = 0; 
    len = strlen(romanNum); 
    int count[1]; 

    for(int i = 0; i < len; i++) 
    {   
      switch(romanNum[i]) 
      { 
       case 'M': 
         count[i] = 1000; 
         break; 
       case 'm': 
         count[i] = 1000; 
         break; 
       case 'D': 
         count[i] = 500; 
         break; 
       case 'd': 
         count[i] = 500; 
         break; 
       case 'C': 
         count[i] = 100; 
         break; 
       case 'c': 
         count[i] = 100; 
         break; 
       case 'L': 
         count[i] = 50; 
         break; 
       case 'l': 
         count[i] = 50; 
         break; 
       case 'X': 
         count[i] = 10; 
         break; 
       case 'x': 
         count[i] = 10; 
         break; 
       case 'V': 
         count[i] = 5; 
         break; 
       case 'v': 
         count[i] = 5; 
         break; 
       case 'I': 
         count[i] = 1; 
         break; 
       case 'i': 
         count[i] = 1; 
         break; 
       default: 
         cout << "Error.." << endl; 
      } 
      total = total + count[0]; 
    } 
    return total; 
}; 

我的主：

#include "stdafx.h" 
#include <iostream> 
#include <iomanip> 
#include "romanType.h" 

using namespace std; 

int main() 
{ 
    romanType r; 

    char romanNum; 
    char choice; 
    int decimal; 
    int total; 

    cout << "Hello! Please enter your Roman Numeral: " << endl; 
    cin >> romanNum; 
    cout << endl; 


    r.setRoman(romanNum); 
    r.convertRoman(total); 

    cout << "Do you want the Roman Numeral or the Decimal?" << endl; 
    cout << "Press [D] for Decimal!" << endl << "Press [R] for Roman Numeral!" << endl; 

    cin >> choice; 

    if (choice == 'D' || choice == 'd') 
     r.printDecimal(total); 
    else if (choice == 'R' || choice == 'r') 
     r.printRoman(romanNum); 
    else 
     cout << "That wasn't the right button!" << endl; 

    system ("pause"); 
    return 0; 
} 

我很確定我走在正確的軌道上。很高興看到有關我的錯誤的任何提示或建議。

預先感謝

Answer 1

從只是一個快速瀏覽一下代碼，我可能會建議你的變量在每一步的數值翻翻調試窗口。我所看到的是兩個變量，一個是名爲romanNum的char類型，另一個是名爲romanNum的char數組。它有點混亂，但可以工作，如果你只是要求用戶使用羅馬數字的單個字符，那麼你根本不需要數組。否則，你可能會得到一個字符串，然後將其轉換爲數組。

從那裏開始，看看是否有幫助。