2014-01-24 103 views
0

好的,下面是程序應該如何工作: 通過運行該程序,它會要求用戶輸入將玩樂途的玩家人數。例如,3.因此將創建3行數組,並將6列作爲默認列。現在在樂透數組中生成隨機數字後。然後它會生成一個獲勝的樂透。比較2個二維數組JAVA

問題是在這裏: 我已經完成了生成球員的樂透和獲獎樂透的部分。不過,我無法將獲勝樂透與玩家樂透相比。例如:

播放機0:1 15 30 41 56 12

播放機1:31 65 78 43 29 8

玩家2:41 28 1 6 38 14

獲獎樂透:15 30 56 12 41 1

即使排序不準確,獲勝者應該是玩家0。 但問題是我不能比較二維數組。

下面的代碼:

import javax.swing.*; import java.util.*; public class test{ public static void main(String asd[]){ int players = Integer.parseInt(JOptionPane.showInputDialog("Any NUMBER of PLAYERS\n[0] to exit")); while(players != 0) { int typeOfLotto = Integer.parseInt(JOptionPane.showInputDialog("Type:\n[42] - SixFortyTwo\n[45] - SixFortyFive\n" + "[49] - SixFortyNine\n[55] - SixFiftyFive")); String output="", playersLotto="", winning=""; int taya = 6; int index; int[][] Lotto = new int[players][taya]; int[][] winningLotto = new int[1][taya]; for(index = 0; index<players; index++) { for(int column = 0; column<6; column++) { Lotto[index][column] = numberGen(typeOfLotto,Lotto,index); output += Lotto[index][column] + " "; } playersLotto += "Player " + index + ": " + output +"\n"; output=""; } //winning lotto for(int column = 0; column<6; column++) { winningLotto[0][column] = winningNumberGen(typeOfLotto,winningLotto); winning += winningLotto[0][column] + " "; if(column==5) winning = "Winning lotto: " + winning; } String win = checking(Lotto,winningLotto,players); JOptionPane.showMessageDialog(null, playersLotto + "\n" + winning + "\n" + win); players = Integer.parseInt(JOptionPane.showInputDialog("Any NUMBER of PLAYERS\n[0] to exit")); } } public static int numberGen(int typeOfLotto,int Lotto[][],int index) { int random=0, loop=0; if(typeOfLotto == 42) { random = (int)(1+Math.random()*42); for(loop=0; loop<6; loop++) { if(Lotto[index][loop] == random) return numberGen(typeOfLotto,Lotto,index); } } return random; } //winning public static int winningNumberGen(int typeOfLotto,int winningLotto[][]) { int random=0, loop=0; if(typeOfLotto == 42) { random = (int)(1+Math.random()*42); for(loop=0; loop<6; loop++) { if(winningLotto[0][loop] == random) return winningNumberGen(typeOfLotto,winningLotto); } } return random; } public static String checking(int Lotto[][], int winningLotto[][], int players) { int win[] = new int[6]; int panalo=0; String winner="", output=""; for(int index=0; index<players;index++) { for(int loop=0;loop<6;loop++) { if(winningLotto[0][0] == Lotto[index][loop]) win[loop] = Lotto[index][loop]; if(winningLotto[0][1] == Lotto[index][loop]) win[loop] = Lotto[index][loop]; if(winningLotto[0][2] == Lotto[index][loop]) win[loop] = Lotto[index][loop]; if(winningLotto[0][3] == Lotto[index][loop]) win[loop] = Lotto[index][loop]; if(winningLotto[0][4] == Lotto[index][loop]) win[loop] = Lotto[index][loop]; if(winningLotto[0][5] == Lotto[index][loop]) win[loop] = Lotto[index][loop]; } } if(win[0] > 0) panalo++; if(win[1] > 0) panalo++; if(win[2] > 0) panalo++; if(win[3] > 0) panalo++; if(win[4] > 0) panalo++; if(win[5] > 0) panalo++; if(panalo > 3) { for(int loop=0;loop<6;loop++) { winner += win[loop] + " "; } output = "Winner: " + winner; } else if(panalo < 3) output = "no winner"; return output; } }

我沒有,因爲我還在一個第一年的大學有很多關於Java的知識。那麼我可以問簡單的代碼嗎?我想在for循環中進行比較。我只知道基本。我希望最簡單的代碼可以做到。

修訂新增1層的方法來檢查它爲1的球員,但犯規超過1

UPDATE回答它自己。

回答

1

首先排序贏得樂透

Arrays.sort(winninglotto); 

然後爲您的每個球員得到的數字數組排序,然後看看它們是否等於贏得樂透

Arrays.sort(playernumbers); 
return Arrays.equals(playernumbers, winninglotto); 

這樣的:

public static String checking(int Lotto[][], int winningLotto[][], int players) 
{ 
Arrays.sort(winningLotto[0]); 
for(int i =0; i < players;i++){ 
    Arrays.sort(Lotto[i]); 
    if(Arrays.equals(Lotto[i], winningLotto[0])){ 
     //we have a winnder 
    } 
} 
} 
+0

我將這個應用於main還是我會創建一個新的方法? – lazygeniusLANZ

+0

還有如何分類樂透數組的樂透號碼。 – lazygeniusLANZ