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好的,下面是程序應該如何工作: 通過運行該程序,它會要求用戶輸入將玩樂途的玩家人數。例如,3.因此將創建3行數組,並將6列作爲默認列。現在在樂透數組中生成隨機數字後。然後它會生成一個獲勝的樂透。比較2個二維數組JAVA
問題是在這裏: 我已經完成了生成球員的樂透和獲獎樂透的部分。不過,我無法將獲勝樂透與玩家樂透相比。例如:
播放機0:1 15 30 41 56 12
播放機1:31 65 78 43 29 8
玩家2:41 28 1 6 38 14
獲獎樂透:15 30 56 12 41 1
即使排序不準確,獲勝者應該是玩家0。 但問題是我不能比較二維數組。
下面的代碼:
import javax.swing.*;
import java.util.*;
public class test{
public static void main(String asd[]){
int players = Integer.parseInt(JOptionPane.showInputDialog("Any NUMBER of PLAYERS\n[0] to exit"));
while(players != 0)
{
int typeOfLotto = Integer.parseInt(JOptionPane.showInputDialog("Type:\n[42] - SixFortyTwo\n[45] - SixFortyFive\n" +
"[49] - SixFortyNine\n[55] - SixFiftyFive"));
String output="", playersLotto="", winning="";
int taya = 6;
int index;
int[][] Lotto = new int[players][taya];
int[][] winningLotto = new int[1][taya];
for(index = 0; index<players; index++)
{
for(int column = 0; column<6; column++)
{
Lotto[index][column] = numberGen(typeOfLotto,Lotto,index);
output += Lotto[index][column] + " ";
}
playersLotto += "Player " + index + ": " + output +"\n";
output="";
}
//winning lotto
for(int column = 0; column<6; column++)
{
winningLotto[0][column] = winningNumberGen(typeOfLotto,winningLotto);
winning += winningLotto[0][column] + " ";
if(column==5)
winning = "Winning lotto: " + winning;
}
String win = checking(Lotto,winningLotto,players);
JOptionPane.showMessageDialog(null, playersLotto + "\n" + winning + "\n" + win);
players = Integer.parseInt(JOptionPane.showInputDialog("Any NUMBER of PLAYERS\n[0] to exit"));
}
}
public static int numberGen(int typeOfLotto,int Lotto[][],int index)
{
int random=0, loop=0;
if(typeOfLotto == 42)
{
random = (int)(1+Math.random()*42);
for(loop=0; loop<6; loop++)
{
if(Lotto[index][loop] == random)
return numberGen(typeOfLotto,Lotto,index);
}
}
return random;
}
//winning
public static int winningNumberGen(int typeOfLotto,int winningLotto[][])
{
int random=0, loop=0;
if(typeOfLotto == 42)
{
random = (int)(1+Math.random()*42);
for(loop=0; loop<6; loop++)
{
if(winningLotto[0][loop] == random)
return winningNumberGen(typeOfLotto,winningLotto);
}
}
return random;
}
public static String checking(int Lotto[][], int winningLotto[][], int players)
{
int win[] = new int[6];
int panalo=0;
String winner="", output="";
for(int index=0; index<players;index++)
{
for(int loop=0;loop<6;loop++)
{
if(winningLotto[0][0] == Lotto[index][loop])
win[loop] = Lotto[index][loop];
if(winningLotto[0][1] == Lotto[index][loop])
win[loop] = Lotto[index][loop];
if(winningLotto[0][2] == Lotto[index][loop])
win[loop] = Lotto[index][loop];
if(winningLotto[0][3] == Lotto[index][loop])
win[loop] = Lotto[index][loop];
if(winningLotto[0][4] == Lotto[index][loop])
win[loop] = Lotto[index][loop];
if(winningLotto[0][5] == Lotto[index][loop])
win[loop] = Lotto[index][loop];
}
}
if(win[0] > 0)
panalo++;
if(win[1] > 0)
panalo++;
if(win[2] > 0)
panalo++;
if(win[3] > 0)
panalo++;
if(win[4] > 0)
panalo++;
if(win[5] > 0)
panalo++;
if(panalo > 3)
{
for(int loop=0;loop<6;loop++)
{
winner += win[loop] + " ";
}
output = "Winner: " + winner;
}
else if(panalo < 3)
output = "no winner";
return output;
}
}
我沒有,因爲我還在一個第一年的大學有很多關於Java的知識。那麼我可以問簡單的代碼嗎?我想在for循環中進行比較。我只知道基本。我希望最簡單的代碼可以做到。
修訂新增1層的方法來檢查它爲1的球員,但犯規超過1
UPDATE回答它自己。
我將這個應用於main還是我會創建一個新的方法? – lazygeniusLANZ
還有如何分類樂透數組的樂透號碼。 – lazygeniusLANZ