在java中使用命令行處理文件名

Question

我試圖通過命令行接受3個文件名。這是我試過的代碼，但沒有工作.. ??請幫助

public class MedicalStudentMatcher { 

enum Arguments { 
    HospitalFile, ResidentFile, OutputFile 
}; 

/** 
* @param args 
*/ 
public static void main(String[] args) { 

    //Retrieve file locations from command line arguments 
    String hospitalFile = ""; 
    String residentFile = ""; 
    String outFile = ""; 


    if (args.length > 2){ 
     hospitalFile = args[Arguments.HospitalFile.ordinal()]; 
     residentFile = args[Arguments.ResidentFile.ordinal()]; 
     outFile = args[Arguments.OutputFile.ordinal()]; 
    } else { 
     System.out 
       .println("Please include names for the preference files and output file when running the application.\n " 
         + "Usage: \n\tjava MedicalStudentMatcher hospital.csv student.csv out.txt\n"); 
     return; 
    } 

Answer 1

做一些調試。打印你的命令行參數的長度以及每一個參數

類似：

System.out.println(args.length); 

for(String arg: args) 
{ 
    System.out.println(arg); 
} 

這樣，您將看到您傳遞什麼程序作爲參數。