在c＃中創建一個重載的方法

Question

我正在嘗試創建持有客戶聯繫信息和地址信息的類。

我目前正在嘗試重載方法，希望能凝結我的代碼，並且在做各種方法會做同樣的事情時更容易閱讀。此外，我正在使用NUnit，因爲這些是我創建的集成測試，所以這是隨機生成器的來源。以下是我迄今爲止：

public static Address BuildAddress() 
    { 
     var gen = new RandomGenerator(); 
     return BuildAddress(gen.Phrase(10)); 
    } 

    //build a billing address 
    public static AddressInfo BuildAddress(string name) 
    { 
     return BuildAddress(name, "USA"); 
    } 

    public static Address BuildAddress(string name, string country) 
    { 
     var gen = new RandomGenerator(); 

     var address = Builder<AddressInfo>.CreateNew() 
      .With(x => x.Name = name) 
      .And((x => x.Address1 = gen.Int() + " " + gen.Phrase(10) + " Street")) 
      .And(x => x.City = gen.Phrase(15)) 
      .And(x => x.StateOrProvince = gen.Phrase(2)) 
      .And(x => x.Country = country) 
      .And(x => x.PostalCode = "32561"). 
      Build(); 

     return address; 

我做了這一點，但我也想我需要添加另一個代碼塊的郵寄地址。請讓我知道是否有一個更短的方法來做到這一點。

謝謝！

Answer 1

如果我理解正確的話，你想縮短上面的代碼，即你有方法重載鏈...你可以使用默認的屬性格式，即：

public static Address BuildAddress(string name, int phrase = 10, string country = "USA") 
{ 
     var gen = new RandomGenerator(); 

     var address = Builder<AddressInfo>.CreateNew() 
      .With(x => x.Name = name) 
      .And((x => x.Address1 = gen.Int() + " " + gen.Phrase(10) + " Street")) 
      .And(x => x.City = gen.Phrase(15)) 
      .And(x => x.StateOrProvince = gen.Phrase(2)) 
      .And(x => x.Country = country) 
      .And(x => x.PostalCode = "32561"). 
      Build(); 

     return address; 
} 

你可以調用它喜歡..

ClassName.BuilderAddress("my name"); 

或..

ClassName.BuilderAddress("my name", 5); 

或..

ClassName.BuilderAddress("my name", 7, "Ireland"); 

建議回答下面您的評論：（就這一個不是100％確定），生成你的意思是假數據

public static T BuildAddress(string name, int phrase = 10, string country = "USA") 
{ 
     var gen = new RandomGenerator(); 

     var address = Builder<T>.CreateNew() 
      .With(x => x.Name = name) 
      .And((x => x.Address1 = gen.Int() + " " + gen.Phrase(10) + " Street")) 
      .And(x => x.City = gen.Phrase(15)) 
      .And(x => x.StateOrProvince = gen.Phrase(2)) 
      .And(x => x.Country = country) 
      .And(x => x.PostalCode = "32561"). 
      Build(); 

     return address; 
} 

Answer 2

您可能需要考慮可選參數和命名參數。

http://msdn.microsoft.com/en-us/library/dd264739.aspx