這部分解決方案應該給你的提示。 我已經改變了一些東西更加自我解釋。
還要注意,使用固定大小(64像素)的圖像容器和圖像有自己的背景顏色...
它是基於你的小提琴。 updated fiddle (with comments)
HTML:
<ul>
<li>
<img src=img-1.jpg class=images alt="">
</li>
<li>
<img src=img-4.jpg class=images alt="">
</li>
<li>
<img src=img-3.jpg class=images alt="">
</li>
<li>
<img src=img-2.jpg class=images alt="">
</li>
</ul>
CSS:
/* this is the visible area */
ul {
display: inline-block;
border: 2px solid #444;
height: 64px;
width: 256px;
overflow: hidden;
position: relative;
padding: 0px;
}
/* this element will shift to the left */
li {
list-style: none;
width: 100%;
height: inherit;
position: absolute;
top: 0px;
left: 0px;
width: 64px;
height: inherit;
}
li img {
display: block;
background-color: black;
/* to match the size of <li> element */
width: 100%;
height: 100%;
}
li:nth-of-type(1) img {
background-color: red;
}
li:nth-of-type(2) img {
background-color: green;
}
li:nth-of-type(3) img {
background-color: blue;
}
li:nth-of-type(4) img {
background-color: black;
}
JS:
// the list of <li> elements, these will shift from right to left
var elements = document.getElementsByTagName('li');
// this function is used to assign starting position to each <li> element
function init() {
var pos, li;
for (var i = 0; i < elements.length; i++)
{
li = elements[i];
// assign starting position to <li>
// the first <li> will have position (0 * 64) = 0px from the left
// the second <li> (1 * 64) = 64px
// the third <li> (2 * 64) = 128px
// etc.
li.style.left = (i * 64) + 'px';
}
}
// In this funciton we are moving each <li> by 64px to the left.
function slide() {
var pos, // this will hold the numeric value (number of px from the left)
li, // this will reference the <li>
cssPos, // this will hold the CSS left position of the <li> element
strNumPos // this will hold the left position without px at the end (it is strill string value);
for (var i = 0; i < elements.length; i++)
{
// store the <li>
li = elements[i];
// get the CSS left position eg: "64px"
cssPos = li.style.left;
// get the numeric string value without "px" eg: "64"
strNumPos = cssPos.replace('px', '');
// convert the string to a number eg: 64
pos = parseInt(strNumPos, 10);
// since we are shifting each <li> by 64px to the left, it may happen that the
// <li> would be pushed outside of the visible area eg: -64px to the left.
// The visible area is a rectangle 256px wide.
if (pos <= 0)
{
// The <li> would be pushed outside of the visible area so to create carousel effect
// we will place the <li> at the end of the visible area.
// the left position will be 196px
pos = (elements.length - 1) * 64;
}
else
{
// just update the position eg: 128 - 64 = 64
pos = (pos - 64);
}
// set new position to <li>
li.style.left = pos + 'px';
}
}
// start with arranging the layout
init();
// start the carousel effect
setInterval(slide, 1500);
UPDATE 上面的例子是有點邪惡,我將結束地獄的t帽子:)
我創建了一個new fiddle與簡單的傳送帶和最小的JavaScript。
基本思想是使用vanilla DOM方法.appendChild()在列表末尾附加第一個<li>
。
var list = document.getElementsByTagName("li"),
ul = document.getElementsByTagName("ul")[0];
function slide() {
// use appendChild() to simply append the first image at the end of the <ul>
ul.appendChild(list[0]);
}
setInterval(slide, 1500);
謝謝,但我不明白。我想這對初學者來說很複雜。我添加了一些評論,顯示我在這裏丟失了什麼https://jsfiddle.net/nmeri17/ezgux45b/4/ –
我在這裏添加了解釋到你的小提琴:https://jsfiddle.net/ezgux45b/6/ – CodeLama
你好@ CodeLama誠摯歉意我無法提前回復。我一直試圖理解你的代碼,但即使我仍然不能,我明白你想要做什麼。所以我在這個小提琴https://jsfiddle.net/nmeri17/wdcez6rj/2/的基礎上做了些什麼,儘管它不起作用。你可以指出我的錯誤 –