在單詞中查找元音的函數？

Question

我有一個問題，我不得不使用一個函數來輸出單詞中的元音並輸出有多少元音。我剛剛在當地大學學習了一門計算機課程，對這件事情是新鮮的，它有點過頭了。

我試過，但是這是我得到的時候我跑了它：

TypeError: vowel() takes 0 positional arguements but 1 was given 

我的代碼：

def vowel(): 
    array = [] 
    counter = 0 
    for i in word: 
    if i in ("a","e","i","o","u"): 
     counter+=1 
     array.append(i) 
    return (array, counter) 

word = input("Enter your word") 
function = vowel(word) 
print(function) 

Answer 1

在函數的定義，你忘了提供word

def vowel (word): 
    array = [] 
    counter = 0 
    for i in word: 
    if i in ("a","e","i","o","u"): 
     counter+=1 
     array.append(i) 
    return (array, counter) 


word = input("Enter your word") 
function = vowel(word) 
print(function) 

要閱讀更多關於位置參數的信息，請參閱此帖Positional argument v.s. keyword argument

Answer 2

錯誤不言自明。 您聲明瞭函數元音以0參數播種。

def vowel(): 

，你把它叫做一個參數播種它：

function = vowel(word) 

你應該做的是：

def vowel (word): 
    array = [] 
    counter = 0 
    for i in word: 
     if i in ("a","e","i","o","u"): 
     counter+=1 
     array.append(i) 
    return (array, counter) 

Answer 3

其實，錯誤的是簡單的。

當您定義函數元音時，它不會收到任何參數。

它應該是這樣的：

def vowel (word): 

希望我可以幫助你：d

Answer 4

您可以使用一個函數，然後簡單的列表理解：

def vowel(word): 
    array = [i for i in word if i in ("a","e","i","o","u")] 
    counter = len(array) 
    return array, counter 

word = input("Enter your word") 
function = vowel(word) 
print(function) 

Answer 5

參數的個數在函數定義和函數調用中給出的應該是相同的。在函數定義中，您已寫入def vowel():，但在調用function = vowel(word)時，您正在爲函數提供參數。因此它會拋出一個錯誤。您可以將其修改爲：

def vowel(word): 
    array = [] 
    counter = 0 
    for i in word: 
    if i in ("a","e","i","o","u"): 
     counter+=1 
     array.append(i) 
    return (array, counter) 

word = input("Enter your word") 
function = vowel(word) 
print(function)