2012-02-13 53 views
7

使用httplib2和urllib2,我試圖從這個URL中獲取頁面,但是他們都沒有解決,最終導致了這個異常。爲什麼這個url用httplib2和urllib2引發BadStatusLine?

content = conn.request(uri="http://www.zdnet.co.kr/news/news_print.asp?artice_id=20110727092902") 
Traceback (most recent call last): 
    File "<stdin>", line 1, in <module> 
    File "/usr/lib/python2.7/dist-packages/httplib2/__init__.py", line 1129, in request 
    (response, content) = self._request(conn, authority, uri, request_uri, method, body, headers, redirections, cachekey) 
    File "/usr/lib/python2.7/dist-packages/httplib2/__init__.py", line 901, in _request 
    (response, content) = self._conn_request(conn, request_uri, method, body, headers) 
    File "/usr/lib/python2.7/dist-packages/httplib2/__init__.py", line 871, in _conn_request 
    response = conn.getresponse() 
    File "/usr/lib/python2.7/httplib.py", line 1027, in getresponse 
    response.begin() 
    File "/usr/lib/python2.7/httplib.py", line 407, in begin 
    version, status, reason = self._read_status() 
    File "/usr/lib/python2.7/httplib.py", line 371, in _read_status 
    raise BadStatusLine(line) 

HTTP標頭是這樣

http://www.zdnet.co.kr/news/news_print.asp?artice_id=20110727092902 

GET /news/news_print.asp?artice_id=20110727092902 HTTP/1.1 
Host: www.zdnet.co.kr 
User-Agent: Mozilla/5.0 (Windows NT 5.1; rv:10.0.1) Gecko/20100101 Firefox/10.0.1 
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 
Accept-Language: ko-kr,ko;q=0.8,en-us;q=0.5,en;q=0.3 
Accept-Encoding: gzip, deflate 
Connection: keep-alive 
Cookie: RMID=7d83495d4f336fe0; __utma=37206251.1552605885.1328771258.1328771258.1329070845.2; __utmz=37206251.1328771258.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none); ASPSESSIONIDCSQCQTDD=BCLEHPPDEPHEBJDLCFNDMKDN; __utmc=37206251; ASPSESSIONIDSSQCQQCB=MJPLMOJAFPDFCLONCANBIKHN; _EXEN=2 
X-FireLogger: 1.2 

HTTP/1.1 200 OK 
Date: Mon, 13 Feb 2012 18:02:56 GMT 
Content-Length: 19158 
Content-Type: text/html;charset=UTF-8; Charset=UTF-8 
Set-Cookie: ASPSESSIONIDSQSDQRDB=NGAIFHKAGDIOGEMANAOLLKKF; path=/ 
Cache-Control: private 

任何線索?

+0

請發佈您的connect語句。 – Nix 2012-02-13 18:16:53

回答

3

也能正常工作對我來說:

import urllib2 

opener = urllib2.build_opener() 

headers = { 
    'User-Agent': 'Mozilla/5.0 (Windows NT 5.1; rv:10.0.1) Gecko/20100101 Firefox/10.0.1', 
} 

opener.addheaders = headers.items() 
response = opener.open("http://www.zdnet.co.kr/news/news_print.asp?artice_id=20110727092902") 

print response.headers 
print response.read() 

網站丟棄不用User-Agent字符串出現的所有請求。

1

看起來這個網頁不允許你的用戶代理。你可以這樣改變它:

>>> import urllib2 
>>> user_agent = 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)' 
>>> headers = { 'User-Agent' : user_agent } 
>>> r = urllib2.Request('http://www.zdnet.co.kr/news/news_print.asp?artice_id=20110727092902', headers=headers) 
>>> fd = urllib2.urlopen(r) 
>>> print fd[20:] 
'<!DOCTYPE html PUBLI' 
2

在我的代碼,當我使用

from urllib2 import urlopen 
    content = urlopen(page).read() 

出現異常。然而,當我使用

import urllib 
    content = urllib.urlopen(page).read() 

一切正常。 也許它會幫助你。

+1

這解決了我的問題。謝謝。但很高興知道爲什麼urllib2不起作用。 – 2015-03-15 18:55:25

4

對於所有類似的問題在安裝httplib2的0.8之後這裏就結束了百姓:

版本0.8已經與相關方面處理與HTTP保持活動迴歸。查看錯誤報告:https://code.google.com/p/httplib2/issues/detail?id=250

這個問題有一個解決方法,但目前尚未發佈。直到那時才使用httplib2 0.7.7。

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