JSON解析時名稱是正則表達式（日期）

Question

道歉，如果主題標題不準確，我真的不知道如何表達它（沒有雙關語意圖）。 我必須用類似於下面的結構來解析JSON。在這個文件中有幾個Date數組：每個數組都以yyyy-MM-dd的形式命名，但是我不知道文件中的具體日期（所以我不能提取數組其名稱）。我還能怎樣得到它？ 我正在使用json.simple for Java解析文件。我不指望一個答案，告訴我如何使用該庫專門做它，但如果有人知道，這將是一個獎金:)

"2011-05-15":[ 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"AnahiHappyBDay", 
     "name":"AnahiHappyBDay" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Puerto Ricans", 
     "name":"Puerto Ricans" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Epic Movie", 
     "name":"Epic Movie" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Lee Soonkyu", 
     "name":"Lee Soonkyu" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"MC1123", 
     "name":"MC1123" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Dominique Strauss-Kahn", 
     "name":"Dominique Strauss-Kahn" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"WeLoveNickJonas", 
     "name":"WeLoveNickJonas" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Ripper Stefan", 
     "name":"Ripper Stefan" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Luc\u00eda P\u00e9rez", 
     "name":"Luc\u00eda P\u00e9rez" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"DB5K", 
     "name":"DB5K" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"WeSupportYouGomez", 
     "name":"WeSupportYouGomez" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"LSnoAltasHoras", 
     "name":"LSnoAltasHoras" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Azerbaijan", 
     "name":"Azerbaijan" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Eurovision", 
     "name":"Eurovision" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Derek Boogaard", 
     "name":"Derek Boogaard" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Terry Wogan", 
     "name":"Terry Wogan" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"FMI", 
     "name":"FMI" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"WorldLovesSwift", 
     "name":"WorldLovesSwift" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"WorldWarIV", 
     "name":"WorldWarIV" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Jedward", 
     "name":"Jedward" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"GAGA10MILLION", 
     "name":"GAGA10MILLION" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Stefan Raab", 
     "name":"Stefan Raab" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Manchester United Campe\u00f3n", 
     "name":"Manchester United Campe\u00f3n" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Derek Mooney", 
     "name":"Derek Mooney" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Chord Overstreet", 
     "name":"Chord Overstreet" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"IMF", 
     "name":"IMF" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Joe Buck", 
     "name":"Joe Buck" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"\u0410\u0437\u0435\u0440\u0431\u0430\u0439\u0434\u0436\u0430\u043d", 
     "name":"\u0410\u0437\u0435\u0440\u0431\u0430\u0439\u0434\u0436\u0430\u043d" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"Wango Tango", 
     "name":"Wango Tango" 
    }, 
    { 
     "promoted_content":null, 
     "events":null, 
     "query":"AlwaysRihannaNavy", 
     "name":"AlwaysRihannaNavy" 
    } 
    ], 

Answer 1

我不太清楚，如果我明白你的問題，但我假設你想要一個日期鍵列表。

Parsering這與json.simple應導致一個JSONObject這是一個地圖，所以它的keySet()方法會給你你需要的東西：

JSONObject<String, Object> obj = (JSONObject<String, Object>)JSONValue.parse(s); 
for (String key in obj.keySet()) { 
    // do something with key 
} 

Answer 2

其實我不是很明白你的意思...... 然而，我想我有一個解決方案[使用GSON（谷歌圖書館）] 看完你的數據後，我認爲我們可以創建一個類。像這樣

public class Foo{ 
    private Date date/* or ID ?*/; 
    private List<Content> contents; //a class defined blow 
    /* constructors and methods */ 
} 

public class Content{ 
    private String promoted_content;// Or a class? I'm not sure, because I found all of them is null 
    private String events;// same as promoted_content 
    private String query; 
    private String name;  
    /* constructors and methods */ 
} 

現在，用gson解析你的數據。像這樣

Gson gson = new Gson();//maybe you wanna read docs of gson for more detail 
Foo foo = gson.fromjson(/*your data*/, Foo.class); 

在這裏你知道你有一個名爲Foo的對象，你可以得到它的值。我注意到，你說也許有不止一個「日期」，所以我們可以創建一個包含List的新類。