使用otool（遞歸）來查找應用程序所需的共享庫

Question

我有一個Cocoa應用程序，它使用otool查找應用程序需要正常工作所需的共享庫。例如，假設我在使用QTKit.framework的應用程序上運行otool -L。我得到的程序（包括像Cocoa.framework和AppKit.framework的基本框架）中使用的共享庫的列表：

/System/Library/Frameworks/QTKit.framework/Versions/A/QTKit (compatibility version 1.0.0, current version 1.0.0) 
/System/Library/Frameworks/CoreFoundation.framework/Versions/A/CoreFoundation (compatibility version 150.0.0, current version 476.0.0) 
    /System/Library/Frameworks/AppKit.framework/Versions/C/AppKit (compatibility version 45.0.0, current version 949.0.0) 

..... and so on for a bunch of other frameworks 

這表明應用程序使用QTKit.framework。但是，如果我使用「otool -L」再次上的二進制文件QTKit.framework（/System/Library/Frameworks/QTKit.framework/Versions/A/QTKit）我得到這樣的：

/System/Library/Frameworks/QTKit.framework/Versions/A/QTKit (compatibility version 1.0.0, current version 1.0.0) 
/System/Library/Frameworks/AudioToolbox.framework/Versions/A/AudioToolbox (compatibility version 1.0.0, current version 1.0.0) 
/System/Library/PrivateFrameworks/CoreMedia.framework/Versions/A/CoreMedia (compatibility version 1.0.0, current version 1.0.0) 
/System/Library/PrivateFrameworks/MediaToolbox.framework/Versions/A/MediaToolbox (compatibility version 1.0.0, current version 1.0.0) 
/System/Library/PrivateFrameworks/VideoToolbox.framework/Versions/A/VideoToolbox (compatibility version 1.0.0, current version 1.0.0) 
/System/Library/PrivateFrameworks/CoreMediaIOServices.framework/Versions/A/CoreMediaIOServices (compatibility version 1.0.0, current version 1.0.0) 
/System/Library/Frameworks/Foundation.framework/Versions/C/Foundation (compatibility version 300.0.0, current version 751.0.0) 
/System/Library/Frameworks/AppKit.framework/Versions/C/AppKit (compatibility version 45.0.0, current version 1038.0.0) 
/System/Library/Frameworks/IOKit.framework/Versions/A/IOKit (compatibility version 1.0.0, current version 275.0.0) 
/System/Library/Frameworks/QuickTime.framework/Versions/A/QuickTime (compatibility version 1.0.0, current version 1584.0.0) 
/System/Library/Frameworks/CoreAudio.framework/Versions/A/CoreAudio (compatibility version 1.0.0, current version 1.0.0) 
/System/Library/Frameworks/OpenGL.framework/Versions/A/OpenGL (compatibility version 1.0.0, current version 1.0.0) 
/System/Library/Frameworks/QuartzCore.framework/Versions/A/QuartzCore (compatibility version 1.2.0, current version 1.6.0) 
/System/Library/Frameworks/IOSurface.framework/Versions/A/IOSurface (compatibility version 1.0.0, current version 1.0.0) 
/System/Library/Frameworks/Carbon.framework/Versions/A/Frameworks/HIToolbox.framework/Versions/A/HIToolbox (compatibility version 1.0.0, current version 435.0.0) 
/usr/lib/libstdc++.6.dylib (compatibility version 7.0.0, current version 7.9.0) 
/usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 123.0.0) 
/usr/lib/libobjc.A.dylib (compatibility version 1.0.0, current version 227.0.0) 
/System/Library/Frameworks/CoreServices.framework/Versions/A/CoreServices (compatibility version 1.0.0, current version 44.0.0) 
/System/Library/Frameworks/CoreFoundation.framework/Versions/A/CoreFoundation (compatibility version 150.0.0, current version 550.0.0) 
/System/Library/Frameworks/ApplicationServices.framework/Versions/A/ApplicationServices (compatibility version 1.0.0, current version 38.0.0) 
/System/Library/Frameworks/CoreVideo.framework/Versions/A/CoreVideo (compatibility version 1.2.0, current version 1.6.0) 

這表明負載應用程序二進制文件中原始otool輸出顯示的更多框架。 有沒有辦法讓otool以遞歸方式運行，這意味着它抓住了應用程序需要的框架，然後進入並搜索每個框架的依賴關係？

Answer 1

不，您將不得不重複運行otool，或合併其解析代碼（here）。不要忘記處理@executable_path。

這在Python（沒有@executable_path，規範化，或文件名與 - 空間支持），因爲這不是試圖調試僞代碼更容易：

import subprocess 

def otool(s): 
    o = subprocess.Popen(['/usr/bin/otool', '-L', s], stdout=subprocess.PIPE) 
    for l in o.stdout: 
     if l[0] == '\t': 
      yield l.split(' ', 1)[0][1:] 

need = set(['/Applications/iTunes.app/Contents/MacOS/iTunes']) 
done = set() 

while need: 
    needed = set(need) 
    need = set() 
    for f in needed: 
     need.update(otool(f)) 
    done.update(needed) 
    need.difference_update(done) 

for f in sorted(done): 
    print f