刪除LaTeX的宏觀跨越多行

Question

我有下面這段代碼的LaTeX，並希望刪除\新出現的所有{「文本跨越多行」}。需要保留「跨越多行的文本」，只有「\ NEW {」和文件「}」中的某個位置需要被刪除，新的括號內應該保持不變。標籤和空格以及換行符需要保留。我已經嘗試編寫一個Python應用程序，但無法提供體面的輸出。最難的部分是你去掉括號的地方（可以在下一行）。

輸入：

\chapter{A \NEW{very} small \NEW{chapter}} 

\begin{itemize} 
    \item \NEW{Bla} 
    \item Dusse 
    \item Mekker 
\end{itemize} 

\NEW{This is new 
    multiline \texttt{text} with some things \TBD{TBD} in between 
    } The end 

輸出（預計）：

\chapter{A very small chapter} 

\begin{itemize} 
    \item Bla 
    \item Dusse 
    \item Mekker 
\end{itemize} 

This is new 
    multiline \texttt{text} with some things \TBD{TBD} in between 
    The end 

在Python自己的解決方案，它的工作原理：

• 讀線
  • 更換\ NEW {occurence帶有標記（0xff的炭）在管線
  • READ C
    • 檢查c是標記，標記組=真，設置嵌套括號marked_cnt，讀下一個字符
    • 否則檢查：C == '{'，增量marked_cnt
    • 否則檢查：C == '}'，標誌着==真，減量marked_cnt
    • 如果marked_cnt == -1，復位標記=假marked_cnt = 0，讀下一個字符
    • 打印 「有效」 字符

 
    #!/usr/bin/env python2.7 
    import sys 

    marker=chr(255) 
    marked=False 
    marked_cnt=0 

    fin = open("file.tex", "r") 
    fout = open("file.tex.out", "w") 

    for line in fin: 
     l = line.replace("\NEW{", marker) 
     for c in l: 
      if c == marker: 
       marked = True 
       marked_cnt = 0 
       continue 
      elif c == '{': 
       marked_cnt += 1 
      elif ((c == '}') and 
       (marked == True)): 
       marked_cnt -= 1 

      if marked_cnt == -1: 
       marked = False 
       marked_cnt = 0 
       continue 

      fout.write(c) 

    fin.close() 
    fout.close() 

Answer 1

嘗試使用正則表達式：

import re 
myRe = re.compile(r'\\NEW{\w+}') 
for match in myRe.findall(myString): 
    newstring = match.replace('\NEW{','') 
    newstring = newstring.replace('}','') 
    myString.replace(match,newstring) 

然而，這並不能消除多行的問題。爲了解決這個問題，直接通過字符串，檢查然後打開和關閉括號：

while s.find('\\NEW{')>-1: 
    position = s.find('\\NEW{') 
    print(position, s[position:position+4]) 
    s = s[0:position]+s[position+5:] 
    trailexist = True 
    openbrackets = 0 

    while trailexist and position<len(s): 
     position +=1 
     print(len(s), position,s[position]) 
     if s[position] == '}' and openbrackets == 0: 
      s = s[:position]+s[position+1:] 
      trailexist = False 
      print("Removed!", position) 
     elif s[position] == '{': 
      openbrackets += 1 
      print('Openbrackets:',openbrackets) 
     elif s[position] == '}' and openbrackets>0: 
      openbrackets -= 1