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預期可以解決數學問題。@Overide toString with Integer。然後將setText設置爲JLabel
被一個INT我送toString
@Override
public String toString(){
return Integer.toString(expected);
}
然後我setText
到JLabel
jl.setText(toString());
當程序運行時顯示它顯示了哈希的答案,而不是。
我假設這必須與Integer.toString
但我在toString方法中調用它。
我在這裏做錯了什麼?
Driver Class
import java.awt.EventQueue;
import java.awt.GridLayout;
import java.awt.event.*;
import javax.swing.*;
public class Driver extends MathProblems {
MathProblems problems = new MathProblems();
String s = "Welcome Students!";
String b = "Start!";
private JFrame f;
private JPanel p;
JFrame frame = new JFrame();
JButton b1 = new JButton(b);
JLabel jl = new JLabel(s);
int i;
public Driver() {
gui();
}
public void gui() {
f = new JFrame("Flash Card Program");
p = new JPanel();
f.setLayout(new GridLayout(2, 1));
f.add(jl);
f.add(p);
p.setLayout(new GridLayout(2, 1));
p.add(b1);
jl.setHorizontalAlignment(JLabel.CENTER);
// pack the frame for better cross platform support
f.pack();
// Make it visible
f.setVisible(true);
f.setSize(560,400); // default size is 0,0
f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
b1.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e){
if(b1.getText().equals("Click For Answer"))
{
problems.run();
jl.setText(toString());
String b = "Next Question";
b1.setText(b);
}
else
{
problems.run();
jl.setText(problems.getQuestion());
String b = "Click For Answer";
b1.setText(b);
}
}
});
}
public static void main(String[] args) {
EventQueue.invokeLater(new Runnable() {
public void run() {
new Driver();
}
});
} // End main Method
} // End class Driver
MathProblems
import java.util.Random;
public class MathProblems {
private static final int MAX_NUMBER = 10;
private static final Random random = new Random();
private int expected = 0;
private String question = "";
public void run() {
final int a = random.nextInt(MAX_NUMBER);
final int b = random.nextInt(MAX_NUMBER);
final int type = random.nextInt(4);
switch (type) {
case 0:
add(a, b);
break;
case 1:
subtract(a, b);
break;
case 2:
multiply(a, b);
break;
case 3:
divide(a, b);
break;
}
}
private void add(final int a, final int b) {
expected = a + b;
askQuestion(a + " + " + b + " = ");
}
private void subtract(final int a, final int b) {
expected = a - b;
askQuestion(a + " - " + b + " = ");
}
private void multiply(final int a, final int b) {
expected = a * b;
askQuestion(a + " * " + b + " = ");
}
private void divide(final int a, final int b) {
expected = a/b;
askQuestion(a + "/" + b + " = ");
}
private void askQuestion(final String question) {
this.question = question;
}
public String getQuestion() {
return question;
}
public int getAnswer() {
return expected;
}
@Override
public String toString(){
return Integer.toString(expected);
}
}
你沒有表現出遠遠不夠的代碼。我懷疑''toString()'覆蓋是在一個不同於你調用'setText'的類上。也許你的意思是'jl.setText(someObject.toString())'。 – chrylis
您可以使用String.valueOf(預期); – Arjit
是的,它是在不同的類。我加了我所有的代碼 – wuno