C++調試斷言失敗。矢量下標超出範圍

Question

我一直在尋找一個解決方案，我似乎正在修復一切與他們的錯誤，但我的仍然無法正常工作。

以下代碼顯示了一個名爲Creature的類的向量，對向量進行排序，然後顯示排序的向量。

// displaying the unsorted vector 
for (int i = 0; i < MAX_NO_CREATURES; i++) 
{ 
    if (creatures[i].getAlive() != 0) // checking to see if a creature exists 
    { 
     for (unsigned int j = 0; j < creatures[i].getAvaFood().size(); j++) 
     { 
      cout << creatures[i].getAvaFood()[j] << " "; 
     } 
    } 
} 

//sorting the vector 
for (int i = 0; i < MAX_NO_CREATURES; i++) 
{ 
    if (creatures[i].getAlive() != 0) // checking to see if a creature exists 
    { 
     creatures[i].bubbleSort(creatures[i].getAvaFood()); // calling a sorting function from creatures[i] passing in the relevant vector (its own.. wait what?) 
    } 
} 

cout << endl; 

// displaying the sorted vector 
for (int i = 0; i < MAX_NO_CREATURES; i++) 
{ 
    if (creatures[i].getAlive() != 0) // checking to see if a creature exists 
    { 
     for (unsigned int x = 0; x < creatures[i].getAvaFood().size(); x++) 
     { 
      cout << creatures[i].getAvaFood()[x] << " "; 
     } 
    } 
} 

當我在錯誤窗口中單擊重試時，Visual Basic將我帶到生物類的這一行。特別是IF聲明。

void Creature::bubbleSort(vector<int> &v) 
{ 
    bool swapped = true; 
    int temp; 
    while (swapped) 
    { 
     swapped = false; 
     for (unsigned int i = 0; i < v.size(); i++) 
     { 
      if (v[i] > v[i + 1]) 
      { 
       temp = v[i]; 
       v[i] = v[i + 1]; 
       v[i + 1] = temp; 
       swapped = true; 
      } 
     } 
    } 
} 

Answer 1

for (unsigned int i = 0; i < v.size(); i++) 
    { 
     if (v[i] > v[i + 1]) 

的for允許i爲所有的值[0，v.size），這意味着你將測試v [v.size]，這是無效的。

for循環更改到

for (unsigned int i = 0; i < v.size() - 1; i++) 

您將需要添加一個檢查v.size（）不爲零。