2016-08-12 15 views
1

我正嘗試在Google Apps腳本中使用Javascript生成一個數組,以便將數組寫入表單。我有一個對象campers,其中包含由唯一編號標識的每個人的對象。當我嘗試訪問該人的記錄時,我得到了未定義的內容。這裏的功能:爲什麼我不能使用對象提供的鍵訪問對象中的值?

function processData(data){ // Returning from client with full object - parse and write to spreadsheet 
    Logger.log(data) 
    var campers = data; // All camper data and headers 
    var headers = campers.headers; // Array of ordered questions 
    var nHeaders = headers.length; 
    var array = []; // Array to build - each row is one camper 

    for (uid in campers){ // All objects in campers object 
    if (uid!='headers'){ // want campers only 
     Logger.log(uid); 
     Logger.log(campers[uid]); 
     var row = []; 
     for (var j=0; j<nHeaders; j++){ // Go through all questions 
     if(campers[uid][headers[j]]) row.push(campers[uid][headers[j]]); // Add that value to the array if it exists 
     else row.push(null); 
     } 
     array.push(row); 
    } 
    } 
    var final = ss.getSheetByName('ParseUpload'); 
    final.getRange("A1").offset(0,0,array.length, nHeaders).setValues(array); 
    return; 
} 

當我運行它,我得到以下日誌:

[16-08-12 02:07:31:240 PDT] {headers=[Card Number, Unique ID, Last Name, First Name, Email, Status], 123456={Status=Non-Attend, Unique ID=123456, Email=[email protected], First Name=John, Card Number=456789012, Last Name=Doe}, 987654={Status=Attend, Unique ID=987654, [email protected], First Name=Jane, Card Number=5, Last Name=Doe}, 1234567={Status=Attend, Unique ID=1234567, [email protected], First Name=John, Card Number=123456789, Last Name=Smith}} 
[16-08-12 02:07:31:298 PDT] 123456 
[16-08-12 02:07:31:299 PDT] undefined 
[16-08-12 02:07:31:300 PDT] 987654 
[16-08-12 02:07:31:301 PDT] undefined 
[16-08-12 02:07:31:301 PDT] 1234567 
[16-08-12 02:07:31:302 PDT] undefined 

爲什麼是它的uid的價值,這絕對是campers的關鍵,對於campers[uid]返回undefined ?我已經通過類似的問題進行了搜索,並找到了如何使用括號表示來訪問對象的參考,但沒有獲得未定義的東西(我認爲)。請告訴我,我在這裏失蹤的事情很明顯,或者如果這確實是重複的,可以指示我另一個問題。

這裏是data結構:

{ 
    "headers": ["Card Number", "Unique ID", "Last Name", "First Name", "Email", "Status"], 
    "123456": { 
     "First Name": "John", 
     "Unique ID": 123456, 
     "Email": "test3#test.edu", 
     "Card Number": 456789012, 
     "Last Name": "Doe", 
     "Status": "Non-Attend" 
    }, 
    "987654": { 
     "First Name": "Jane", 
     "Unique ID": 987654, 
     "Email": "[email protected]", 
     "Card Number": 5, 
     "Last Name": "Doe", 
     "Status": "Attend" 
    }, 
    "1234567": { 
     "First Name": "John", 
     "Unique ID": 1234567, 
     "Email": "[email protected]", 
     "Card Number": 123456789, 
     "Last Name": "Smith", 
     "Status": "Attend" 
    } 
} 

編輯 如果我直接在使用上述結構的功能定義campers,它工作正常:

function processData(){ 
    var campers = { 
    "headers": ["Card Number", "Unique ID", "Last Name", "First Name", "Email", "Status"], 
    "123456": { 
     "First Name": "John", 
     "Unique ID": 123456, 
     "Email": "[email protected]", 
     "Card Number": 456789012, 
     "Last Name": "Doe", 
     "Status": "Non-Attend" 
    }, 
    "987654": { 
     "First Name": "Jane", 
     "Unique ID": 987654, 
     "Email": "[email protected]", 
     "Card Number": 5, 
     "Last Name": "Doe", 
     "Status": "Attend" 
    }, 
    "1234567": { 
     "First Name": "John", 
     "Unique ID": 1234567, 
     "Email": "[email protected]", 
     "Card Number": 123456789, 
     "Last Name": "Smith", 
     "Status": "Attend" 
    } 
} 
    var headers = campers.headers; // Array of ordered questions 
    var nHeaders = headers.length; 
    var array = []; // Array to build - each row is one camper 

    for (uid in campers){ // All objects in campers object 
    if (uid!='headers'){ // want campers only 
     Logger.log(uid); 
     Logger.log(campers[uid]); 
     var row = []; 
     for (var j=0; j<nHeaders; j++){ // Go through all questions 
     if(campers[uid][headers[j]]) row.push(campers[uid][headers[j]]); // Add that value to the array if it exists 
     else row.push(null); 
     } 
     array.push(row); 
    } 

    } 
    Logger.log(array); 
    //var final = ss.getSheetByName('ParseUpload'); 
    //final.getRange("A1").offset(0,0,array.length, nHeaders).setValues(array); 
    return; 
} 

這是否幫助?也許有人可以看到爲什麼本地定義的campers工作,但它作爲data傳入時不起作用。

EDIT 2 我嘗試了一些額外的日誌記錄,在不改變功能的其餘部分:

var keys = Object.keys(campers); 
Logger.log(keys) 
for (var uid in campers){ // All objects in campers object 

    if (uid!='headers'){ // want campers only 
    Logger.log(uid); 
    Logger.log(keys.indexOf(uid)); 
    Logger.log(campers[uid]); 
    Logger.log(campers[keys[0]]); 
    Logger.log(campers[Object.keys(campers)[0]]); 
    Logger.log(campers[123456]); 
    Logger.log(campers['123456']); 
    var row = []; 
    for (var j=0; j<nHeaders; j++){ // Go through all questions 
     if(campers[uid][headers[j]]) row.push(campers[uid][headers[j]]); // Add that value to the array if it exists 
     else row.push(null); 
    } 
    array.push(row); 
    } 
} 

這裏生成的日誌:

[16-08-12 07:37:57:069 EDT] [123456, 987654, 1234567, headers] 
[16-08-12 07:37:57:070 EDT] 123456 
[16-08-12 07:37:57:072 EDT] 0.0 
[16-08-12 07:37:57:073 EDT] undefined 
[16-08-12 07:37:57:074 EDT] undefined 
[16-08-12 07:37:57:075 EDT] undefined 
[16-08-12 07:37:57:075 EDT] undefined 
[16-08-12 07:37:57:076 EDT] undefined 

所以uid中的列表中找到鍵,但它看起來像值不知何故無法訪問。啊!

+0

我看到你的'uid'是一個全局變量。其他函數是否修改'uid'? – melpomene

+0

@melpomene:即使這樣做,在Logger.log(uid);和Logger.log(campers [uid])之間運行該函數是沒有機會的;' –

+0

@ Tiffany:Logger.log (JSON.stringify(data))'log? –

回答

0

我仍然不知道是什麼導致了這個問題,但我發現了一個修復程序。由於TJ.Crowder的意見問我,以顯示JSON.stringify(data)結果,不知道如果對象是不是一個標準的JavaScript對象,我想在進入功能如下:

var data2 = JSON.stringify(data); 
var campers = JSON.parse(data2); 

出於某種原因,該對象轉換爲JSON字符串然後立即回到一個對象的作品。

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