如何在某些情況下已經運行後重新運行開關情況循環

Question

在這一類的銀行中，存在銀行的基本功能，但真正的問題出現在開關情況循環中。

class Bank{ 
    private int Balance; 
    private int Withdrawal; 
    private int Deposit; 
    private int AccountNumber; 

void Transaction(){ 
    Scanner input = new Scanner(System.in); 
    System.out.println("Enter the account number to whose account you     want 
to transfer money"); 
    AccountNumber = input.nextInt(); 
    System.out.println("Enter your current Balance"); 
    Balance= input.nextInt(); 

    } 
void Display(){ 
    System.out.println("Account number "+AccountNumber); 
    System.out.println("Balance is "+ Balance); 
    } 
void deposit(){ 
    Scanner input = new Scanner(System.in); 
    System.out.println("Enter the amount to deposit"); 
    int n =input.nextInt(); 
    Balance+=n; 
} 
void withdraw(){ 
    Scanner input = new Scanner(System.in); 
    System.out.println("Enter the amount to withdraw"); 
    int n =input.nextInt(); 
try { 
    if(n>Balance) 
    throw new Exception("The balance you have is insufficient"); 
    } 
catch(Exception e){ 

System.out.println(e); 
} 
    }//void 

我試圖重新運行開關的情況下循環，輸入查詢一個值之後，我希望它再次詢問用戶的所有選項，我試圖用continue語句，但它表明繼續外循環的錯誤。請幫助

public static void main(String args[])throws Exception{ 

    Bank b1=new Bank(); 
    Scanner input = new Scanner(System.in); 
    System.out.println("Enter the number corrosponding to your option "); 
    System.out.println("1 Set "); 
    System.out.println("2 Display "); 
    System.out.println("3 Deposit"); 
    System.out.println("4 Withdraw"); 
    System.out.println("5 Exit"); 

    int num=input.nextInt(); 
    switch(num){ 
     case 1: 
       b1.Transaction(); 
       //int c =input.nextInt(); 
       //wants user to input value again so switch loop works 
       //again 

       break; 
     case 2: 
       b1.Display(); 
       break; 
     case 3: 
       b1.deposit(); 
       break; 
     case 4: 
       b1.withdraw(); 
       break; 
     case 5: 
      return; 

     } 

    }//psvm 
} 

Answer 1

你可以圍繞開關在重新運行

do{ 
int num=input.nextInt(); 
    switch(num){ 
     case 1: 
       break; 
     case 2: 
       break; 
     case 3: 
       break; 
     case 4: 
       break; 
     case 5: 
      return; 
     } 
}while(num!=some_value_to_exit_switch); 
    } 
} 

Answer 2

我在while環路switch內容將有一個布爾標誌，那麼它會直到你滿意的輸入〜