演繹可變模板連接

Question

所以問題很簡單，編譯器是否應該根據標準推斷出模板連接？

例子：

template<typename... RUN_TIME, typename T, typename... CONSTRUCTION_TIME> 
Runnable<T, RUN_TIME...>* makeRunnable(T (*FunctionType)(CONSTRUCTION_TIME..., RUN_TIME...), CONSTRUCTION_TIME... ct_args) 
{ 
    ... 
} 

int print_function(char arg1, int arg2, const char* arg3); 

makeRunnable<const char*>(print_function, 'C', -3); 

應該編譯能夠推測該功能print_function是正常的傳遞，給出的參數和明確的模板？

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Answer 1

除了問題是什麼標準說什麼編譯器應該能夠做到，這裏的一些TMP，使其在編譯GCC：

/** PackDiff: 
* Template Metafunction to deduce the difference of two parameter packs. 
* To distinguish two packs we have to brace them in two tuples 
*/ 
template <class Tup1, class Tup2> struct PackDiff; 

/** Basic algorithm: (T, X1...) - (T, X2...) = (X1...) - (X2...) */ 
template <class T, class... Pack1, class... Pack2> 
struct PackDiff<std::tuple<T, Pack1...>, std::tuple<T, Pack2...>> 
    : PackDiff<std::tuple<Pack1...>, std::tuple<Pack2...>> {}; 

/** End of recursion: (X1...) -() = (X1...) */ 
template <class... Pack1> 
struct PackDiff<std::tuple<Pack1...>, std::tuple<>> 
{ 
    typedef std::tuple<Pack1...> type; 
}; 

/** Mismatch: (T, X1...) - (U, X2...) is undefined */ 
template <class T1, class... Pack1, class T2, class... Pack2> 
struct PackDiff<std::tuple<T1, Pack1...>, std::tuple<T2, Pack2...>> 
{ typedef struct PACK_MISMATCH {} type; }; 

/** Rest:() - (X2...) is undefined */ 
template <class... Pack2> 
struct PackDiff<std::tuple<>, std::tuple<Pack2...>> 
{ typedef struct LEFT_PACK_TOO_SHORT{} type; }; 



//make Runnable Type of T and a diff tuple: 
template <class T, class Tup1> struct MakeRunnableType; 

template <class T, class... Pack> 
struct MakeRunnableType<T, std::tuple<Pack...>> 
{ typedef Runnable<T, Pack...> type; }; 



template<typename... AllArgs, typename T, typename... SomeArgs> 
auto makeRunnable(T (*FunctionType)(AllArgs...), SomeArgs... ct_args) 
    -> typename MakeRunnableType<T, 
      typename PackDiff<std::tuple<AllArgs...>, 
       std::tuple<SomeArgs...> 
      >::type 
    >::type* 
{ 
    typedef typename PackDiff<std::tuple<AllArgs...>, 
       std::tuple<SomeArgs...> 
      >::type PackDiff_t; 
    typedef typename MakeRunnableType<T, PackDiff_t>::type ReturnType; 
    return new ReturnType(); 
} 

我知道。看起來不漂亮。但是works on GCC.