如何格式化循環中的項目數python

Question

我在線閱讀文件並將其轉換爲JSON。我已經得到了結果工作，但希望數字的格式（23456876到23,456,875和345653到345,653）

data_file = [{"name":"python", "downloads":23456876, "version": "3.4.2", "version_downloads": 345653 }] 

我寫的代碼來獲取值，但如果我用for k in key內tryexcept聲明。它不會轉換，我也用另一種方式，但得到cannot convert automatic fields to mamual formatting or something

titles = ["name", "downloads", "version", "Latest downloads"] 
key = ["name", "downloads", "version", "version_downloads"] 

i = 0 
while i < len(data_file): 
    results = [] 
    for k in key: 
     print("{}: {}".format(titles[key.index(k)], data_file[i][k])) 
    print() 
    i+=1 

結果看起來像現在這樣：

name: python 
downloads: 23456876 
latest version: 3.4.2 
Latest downloads: 345653 

我怎樣才能打印downloads是：

downloads: 2,345,676 
Latest downloads: 345653 

Answer 1

不知道你在做什麼索引，但你可以使用isinstance來檢查整數，如果它是格式化：

data_file = [{"name":"python", "downloads":23456876, "version": "3.4.2", "version_downloads": 345653 }] 


titles = ["name", "downloads", "version", "Latest downloads"] 
key = ["name", "downloads", "version", "version_downloads"] 

for d in data_file: 
    for k in key: 
     val = d[k] 
     if isinstance(val, int): 
      val = "{:,}".format(val) 
     print("{}: {}".format(titles[key.index(k)], val)) 

輸出：

name: python 
downloads: 23,456,876 
version: 3.4.2 
Latest downloads: 345,653 

而非索引的我會用字典的名稱映射並做查詢：

titles = ["name", "downloads", "version", "Latest downloads"] 
key = ["name", "downloads", "version", "version_downloads"] 
match = dict(zip(key,titles)) 
for d in data_file: 
    for k in key: 
     val = d[k] 
     if isinstance(val, int): 
      val = "{:,}".format(val) 
     print("{}: {}".format(match[k], val)) 

輸出：

name: python 
downloads: 23,456,876 
version: 3.4.2 
Latest downloads: 345,653 

如果唯一的區別是"version_downloads"它可能會更簡單，只是檢查一個if。