正則表達式將字符串拆分成連續的字母數字部分

Question

我想將字符串拆分爲連續字母的子字符串，它們共享一些屬性：特別是字母數字（儘管會對通用解決方案感興趣）。

E.g. "string#example[is-like="html"].selectors"

將匹配到[string, #, example, [, is, -, like, =", html, "]., selectors]

任何想法如何做到這一點的正則表達式？謝謝！

編輯：我將通過preg_match_all使用PHP的RegEx引擎。

Answer 1

\w+|\W+ 

1以上後果或非字的一個或多個後果字符

輸出：

Array 
    (
     [0] => string 
     [1] => # 
     [2] => example 
     [3] => [ 
     [4] => is 
     [5] => - 
     [6] => like 
     [7] => =" 
     [8] => html 
     [9] => "]. 
     [10] => selectors 
    ) 

Answer 2

使用word boundary anchor，例如在C＃：

splitArray = Regex.Split(subjectString, @"\b"); 

如果你想避免在字符串的開始/結束的空場比賽，與lookaround assertions結合起來：

splitArray = Regex.Split(subjectString, @"(?<!^)\b(?!$)"); 

說明：

(?<!^) # Assert we're not at the start of the string 
\b  # Match a position between an alnum an a non-alnum character 
(?!$) # Assert we're not at the end of the string, either 

一般解決方案如下所示：

假設您想要在數字（\d）和非數字（\D）之間進行拆分。然後，你可以使用

splitArray = Regex.Split(subjectString, @"(?<=\d)(?=\D)|(?<=\D)(?=\d)"); 

說明：字字符

(?<=\d) # Assert that the previous character is a digit 
(?=\D) # and the next character is a non-digit. 
|  # Or: 
(?<=\D) # Assert that the previous character is a non-digit 
(?=\d) # and the next character is a digit.