tomcat5安裝在cent OS上。我的戰爭檔案無法啓動。我正在使用JAX-WS Web服務。 Catlina.out顯示以下日誌在tomcat5上的應用無法啓動
我有以下的Java版本
java version "1.6.0_22"
OpenJDK Runtime Environment (IcedTea6 1.10.6) (rhel-1.25.1.10.6.el5_8-i386)
OpenJDK Server VM (build 20.0-b11, mixed mode)
SEVERE: Exception sending context initialized event to listener instance of class
com.sun.xml.ws.transport.http.servlet.WSServletContextListener
com.sun.xml.ws.transport.http.servlet.WSServletException: WSSERVLET11: failed to parse runtime descriptor: java.lang.IllegalArgumentException: prefix cannot be "null" when creating a QName
at com.sun.xml.ws.transport.http.servlet.WSServletContextListener.contextInitialized(WSServletContextListener.java:139)
at org.apache.catalina.core.StandardContext.listenerStart(catalina-5.5.23.jar.so)
at org.apache.catalina.core.StandardContext.start(catalina-5.5.23.jar.so)
at org.apache.catalina.manager.ManagerServlet.start(catalina-manager-5.5.23.jar.so)
at org.apache.catalina.manager.HTMLManagerServlet.start(catalina-manager-5.5.23.jar.so)
at org.apache.catalina.manager.HTMLManagerServlet.doGet(catalina-manager-5.5.23.jar.so)
at javax.servlet.http.HttpServlet.service(tomcat5-servlet-2.4-api-5.5.23.jar.so)
at javax.servlet.http.HttpServlet.service(tomcat5-servlet-2.4-api-5.5.23.jar.so)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(catalina-5.5.23.jar.so)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(catalina-5.5.23.jar.so)
at org.apache.catalina.core.StandardWrapperValve.invoke(catalina-5.5.23.jar.so)
at org.apache.catalina.core.StandardContextValve.invoke(catalina-5.5.23.jar.so)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(catalina-5.5.23.jar.so)
at org.apache.catalina.core.StandardHostValve.invoke(catalina-5.5.23.jar.so)
at org.apache.catalina.valves.ErrorReportValve.invoke(catalina-5.5.23.jar.so)
at org.apache.catalina.core.StandardEngineValve.invoke(catalina-5.5.23.jar.so)
at org.apache.catalina.connector.CoyoteAdapter.service(catalina-5.5.23.jar.so)
at org.apache.coyote.http11.Http11Processor.process(tomcat-http-5.5.23.jar.so)
at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(tomcat-http-5.5.23.jar.so)
at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(tomcat-util-5.5.23.jar.so)
at org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(tomcat-util-5.5.23.jar.so)
at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(tomcat-util-5.5.23.jar.so)
at java.lang.Thread.run(libgcj.so.7rh)
Caused by: java.lang.IllegalArgumentException: prefix cannot be "null" when creating a QName
at javax.xml.namespace.QName.<init>(xml-commons-apis-1.3.02.jar.so)
at gnu.xml.stream.XMLParser.getAttributeName(libgcj.so.7rh)
at com.sun.xml.ws.util.xml.XMLStreamReaderFilter.getAttributeName(XMLStreamReaderFilter.java:228)
at com.sun.xml.ws.streaming.XMLStreamReaderUtil$AttributesImpl.<init>(XMLStreamReaderUtil.java:355)
at com.sun.xml.ws.streaming.XMLStreamReaderUtil.getAttributes(XMLStreamReaderUtil.java:198)
at com.sun.xml.ws.transport.http.DeploymentDescriptorParser.parseAdapters(DeploymentDescriptorParser.java:204)
at com.sun.xml.ws.transport.http.DeploymentDescriptorParser.parse(DeploymentDescriptorParser.java:147)
at com.sun.xml.ws.transport.http.servlet.WSServletContextListener.contextInitialized(WSServletContextListener.java:124)
...22 more
請人幫助我走出這個問題。 web.xml中
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee `http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">`
<listener>
<listener-class>
com.sun.xml.ws.transport.http.servlet.WSServletContextListener
</listener-class>
</listener>
<servlet>
<servlet-name>fileserver</servlet-name>
<servlet-class>
com.sun.xml.ws.transport.http.servlet.WSServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>fileserver</servlet-name>
<url-pattern>/fileserver</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>120</session-timeout>
</session-config>
<display-name>FrostBoxServer</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
</web-app>
和太陽javax.xml
<?xml version="1.0" encoding="UTF-8"?>
<endpoints
xmlns="http://java.sun.com/xml/ns/jax-ws/ri/runtime"
version="2.0">
<endpoint
name="FileService"
implementation="org.tml.ws.FileServiceImpl"
url-pattern="/fileserver"/>
</endpoints>
你可以發佈* web.xml *的內容嗎? – vacuum 2012-04-05 09:34:19
和sun-jaxws.xml,請。 – Carlo 2012-04-05 09:35:10
編輯:與web.xml和sun-javax.xml的內容 – Asghar 2012-04-05 10:31:20