用php替換段落中的特定文本模式

Question

我需要使用preg_replace或其他方式替換以'Title：'開頭並以'Article Body：'結尾的文本。替換的文字不會包含上面引用的文字。

如：

標題：

示例文本1

文章正文：

示例文本2

應該輸出只

示例文本2

我如何用php做到這一點？

Answer 1

使用積極/消極lookaheads。

$result = preg_replace('/(?<=Title:).*(?=Article Body:)/s', '\nTest\n', $subject); 

上述正則表達式將取代無論是內部標題：...文章正文：以\ NTEST \ n

說明：

" 
(?<=    # Assert that the regex below can be matched, with the match ending at this position (positive lookbehind) 
    Title:    # Match the characters 「Title:」 literally 
) 
.     # Match any single character 
    *     # Between zero and unlimited times, as many times as possible, giving back as needed (greedy) 
(?=     # Assert that the regex below can be matched, starting at this position (positive lookahead) 
    Article\ Body:  # Match the characters 「Article Body:」 literally 
) 
" 

Answer 2

$str = 'Title: this is sample text Article Body: this is also sample text'; 

// output: this is sample text this is also sample text 
echo preg_replace('~Title: (.*)Article Body: (.*)~', '$1 $2', $str); 

正則表達式是非常有用的，你應該學會如何使用它。網上有很多文章，也可以幫助你。