從表單發送電子郵件 - 協議String.Chars未實現

我有一個簡單的聯繫表格發送email和message字段。我正在使用Mailgun。從表單發送電子郵件 - 協議String.Chars未實現

我可以從控制檯完美地發送電子郵件，但是當我嘗試從形式在UI發送，我收到以下錯誤：

protocol String.Chars not implemented for %Iotc.Contact.Email{__meta__: 
#Ecto.Schema.Metadata<:loaded, "contact_emails">, email: 
"[email protected]", id: 25, inserted_at: ~N[2017-06-15 10:34:26.229957], 
message: "I'd like a cake please.", updated_at: ~N[2017-06-15 10:34:26.229977]}

email_controller.ex

def create(conn, %{"email" => email_params, 
        "email" => %{"email" => email, 
        "message" => message}}) do 

    changeset = Contact.Email.changeset(%Iotc.Contact.Email{}, email_params) 
    case Contact.create_email(email_params) do 
     {:ok, email} -> 
     Iotc.Mailer.send_email(email, message) #<this is the issue. 
     conn 
     |> put_flash(:info, "Email sent") 
     |> redirect(to: email_path(conn, :index)) 
     {:error, changeset} -> 
     conn 
     |> put_flash(:error, "Something went wrong") 
     |> render("index.html", changeset: changeset) 
    end

我試着改變

Iotc.Mailer.send_email(email, message)

到

Iotc.Mailer.send_email(email_params)

但後來我得到

key :to not found in: %{"email" => "[email protected]", "message" => "I'd like a cake please.", "name" => "Simon"}

來源

2017-06-15 Simon Cooper

嘗試'Iotc.Mailer.send_email （email.email，message）'。 – Dogbert

再次感謝@Dogbert，看起來工作。我們用'（email.email，message）'做什麼？ –

模式{:ok, email}陰影與%Iotc.Contact.Email{}結構外email字符串值，而send_email預計第一個參數是公正的電子郵件地址字符串值。您可以通過執行email.email得到的地址值：

case Contact.create_email(email_params) do 
    {:ok, email} -> 
    Iotc.Mailer.send_email(email.email, message) 
    ... 
    ... 
end

，或者你可以因爲你不使用它反正改變忽略返回的結構模式：

case Contact.create_email(email_params) do 
    {:ok, _} -> 
    Iotc.Mailer.send_email(email, message) 
    ... 
    ... 
end

來源

2017-06-15 16:21:26 Dogbert

從表單發送電子郵件 - 協議String.Chars未實現

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