如何將2個參數傳遞給php中的array_map函數？

Question

$sql="select * from question_test where test_id='".$test_id."' and difficulty_level BETWEEN ".$_SESSION['difficulty_start']." and ".$_SESSION['difficulty_end']." and question_id NOT IN ('".implode("', '", array_map('mysqli_real_escape_string', $_SESSION['question_attempt']))."') order by rand()*favourability_level desc"; 

在運行上述代碼我得到一個錯誤：

警告：mysqli_real_escape_string（）期望的是2個參數，1 C中給出：\ XAMPP \ htdocs中\ exam.php上線359

Answer 1

使用一個回調函數，而不是

function array_map_callback($a) 
{ 
    global $con; 
    return mysqli_real_escape_string($con, $a); 
} 

array_map('array_map_callback', $_SESSION['question_attempt']); 

其中$con是連接變量。

所以你$sql變量爲：

$sql="select * from question_test where test_id='".$test_id."' and difficulty_level BETWEEN ".$_SESSION['difficulty_start']." and ".$_SESSION['difficulty_end']." and question_id NOT IN ('".implode("', '", array_map('array_map_callback', $_SESSION['question_attempt']))."') order by rand()*favourability_level desc"; 

，或者你可以用array_walk

array_walk($_SESSION['question_attempt'], function(&$string) use ($con) { 
    $string = mysqli_real_escape_string($con, $string); 
});