PHP腳本不能用冒號讀取XML數據（:)

Question

我試着閱讀YouTube XML數據寬度PHP抱住由於YouTube使用冒號（:)他的API 中）準確地說，這裏是我的腳本使用：

$video = array('/some arrays here,separated width commas/');// array of youtube videos 

$v = preg_replace("/[^A-Za-z0-9\-\_]/","",$_GET["v"]); // make sure "v" parameter is sanitized 

if(!empty($v) && in_array($v,$video)){ //check if parameter "v" is empty and is yours video 
    echo('<object width="853" height="505"><param name="movie" value="http://www.youtube.com/v/'.$v.'&hl=en_US&fs=1&hd=1&color1=0xe1600f&color2=0xfebd01"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/'.$v.'&hl=en_US&fs=1&hd=1&color1=0xe1600f&color2=0xfebd01" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="853" height="505"></embed></object>');  
}else{ 
    foreach($video as $v){ 
     echo(' 
     <div class="tube"><a href="/pages/tube.php?v='.$v.'" class="thickbox"><img style="border:2px solid #000;margin:5px;" alt="" src="http://i1.ytimg.com/vi/'.$v.'/default.jpg"/></a>'); 
     $xmlData = simplexml_load_string(file_get_contents('http://gdata.youtube.com/feeds/api/videos/'.$v.'?fields=title,yt:recorded'));//it should be working if I add fields just separated width commas 

     $title = (string)$xmlData->title; 
     $recorded = (string)$xmlData->recorded;//It should be yt:recorded but I understand that cant use : here! 

     {  echo '<p>'.$recorded.' '.$title.'</p></div>'; } 
    } 
} 

它工作良好的寬度只是標題。是否有可能以某種方式讀取yt：記錄

Answer 1

您需要在嘗試訪問它的值之前首先獲取命名空間。看看方法getNamespaces。使用children你就可以訪問值在命名空間裏：

$namespaces = $entry->getNameSpaces(true); 
$yr = $entry->children($namespaces['yt']); 
echo $yr->recorded;