mysqli_fetch_array返回結果只有一個

Question

我試圖做一個小的MySQL數據庫的一個非常非常簡單的查詢，使用下面的代碼（在$主機適當的值等）：

$connection = mysqli_connect($host, $user_name, $password, $database); 
if (mysqli_connect_errno($connection)) { 
    echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
} 

$result = mysqli_query($connection, "select university from universities_alpha"); 
$row = mysqli_fetch_array($result); 

echo print_r($result); 
echo '<br><br>'; 
echo print_r($row); 

mysqli_close($connection); 

由於你可以看到，我在一個人類可讀的方式打印出來的結果，得到以下特性：

mysqli_result Object ([current_field] => 0 [field_count] => 1 [lengths] => Array ([0] => 19) [num_rows] => 9 [type] => 0) 1 

Array ([0] => Arizona State Univ. [university] => Arizona State Univ.) 1 

有該列的幾個例子的大學，所以我不知道我在做什麼錯。

Answer 1

mysqli_fetch_array每次它被稱爲

時間的工作原理是指針試想以下

$result = mysqli_query($connection, "select university from universities_alpha"); 
$row = mysqli_fetch_array($result); // this is the first row 
$row = mysqli_fetch_array($result); // now it's the second row 
$row = mysqli_fetch_array($result); // third row 

實際顯示的數據，你希望它的方式，我建議你做以下

$rows = array(); 
$result = mysqli_query($connection, "select university from universities_alpha"); 
while($row = mysqli_fetch_array($result)) $rows[] = $row; 
print_r($rows);